view hgext3rd/topic/stack.py @ 1906:5e9ce6310720

stack: show the currently active changeset and unstable ones

Still super basic, but give a basic idea of the feature. We use both symbols and
explicit text because symbols are cool but text is more explicit

# stack.py - code related to stack workflow
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
import collections
from mercurial.i18n import _
from mercurial import error
from mercurial import extensions
from mercurial import obsolete

def getstack(repo, topic):
    # XXX need sorting
    trevs = repo.revs("topic(%s) - obsolete()", topic)
    return _orderrevs(repo, trevs)

def showstack(ui, repo, topic):
    if not topic:
        topic = repo.currenttopic
    if not topic:
        raise error.Abort(_('no active topic to list'))
    for idx, r in enumerate(getstack(repo, topic)):
        # super crude initial version
        symbol = ':'
        state = 'clean'
        if repo.revs('%d and parents()', r):
            symbol = '@'
            state = 'current'
        if repo.revs('%d and unstable()', r):
            symbol = '$'
            state = 'unstable'
        if state == 'clean':
            l = "t%d%s %s\n" % (idx, symbol,
                                repo[r].description().splitlines()[0])
        else:
            l = "t%d%s %s (%s)\n" % (idx, symbol,
                                     repo[r].description().splitlines()[0],
                                     state)
        ui.write(l)

# Copied from evolve 081605c2e9b6

def _orderrevs(repo, revs):
    """Compute an ordering to solve instability for the given revs

    revs is a list of unstable revisions.

    Returns the same revisions ordered to solve their instability from the
    bottom to the top of the stack that the stabilization process will produce
    eventually.

    This ensures the minimal number of stabilizations, as we can stabilize each
    revision on its final stabilized destination.
    """
    # Step 1: Build the dependency graph
    dependencies, rdependencies = builddependencies(repo, revs)
    # Step 2: Build the ordering
    # Remove the revisions with no dependency(A) and add them to the ordering.
    # Removing these revisions leads to new revisions with no dependency (the
    # one depending on A) that we can remove from the dependency graph and add
    # to the ordering. We progress in a similar fashion until the ordering is
    # built
    solvablerevs = collections.deque([r for r in sorted(dependencies.keys())
                                      if not dependencies[r]])
    ordering = []
    while solvablerevs:
        rev = solvablerevs.popleft()
        for dependent in rdependencies[rev]:
            dependencies[dependent].remove(rev)
            if not dependencies[dependent]:
                solvablerevs.append(dependent)
        del dependencies[rev]
        ordering.append(rev)

    ordering.extend(sorted(dependencies))
    return ordering

def builddependencies(repo, revs):
    """returns dependency graphs giving an order to solve instability of revs
    (see _orderrevs for more information on usage)"""

    # For each troubled revision we keep track of what instability if any should
    # be resolved in order to resolve it. Example:
    # dependencies = {3: [6], 6:[]}
    # Means that: 6 has no dependency, 3 depends on 6 to be solved
    dependencies = {}
    # rdependencies is the inverted dict of dependencies
    rdependencies = collections.defaultdict(set)

    for r in revs:
        dependencies[r] = set()
        for p in repo[r].parents():
            try:
                succ = _singlesuccessor(repo, p)
            except MultipleSuccessorsError as exc:
                dependencies[r] = exc.successorssets
                continue
            if succ in revs:
                dependencies[r].add(succ)
                rdependencies[succ].add(r)
    return dependencies, rdependencies

def _singlesuccessor(repo, p):
    """returns p (as rev) if not obsolete or its unique latest successors

    fail if there are no such successor"""

    if not p.obsolete():
        return p.rev()
    obs = repo[p]
    ui = repo.ui
    newer = obsolete.successorssets(repo, obs.node())
    # search of a parent which is not killed
    while not newer:
        ui.debug("stabilize target %s is plain dead,"
                 " trying to stabilize on its parent\n" %
                 obs)
        obs = obs.parents()[0]
        newer = obsolete.successorssets(repo, obs.node())
    if len(newer) > 1 or len(newer[0]) > 1:
        raise MultipleSuccessorsError(newer)

    return repo[newer[0][0]].rev()

class MultipleSuccessorsError(RuntimeError):
    """Exception raised by _singlesuccessor when multiple successor sets exists

    The object contains the list of successorssets in its 'successorssets'
    attribute to call to easily recover.
    """

    def __init__(self, successorssets):
        self.successorssets = successorssets