author | Matt Mackall <mpm@selenic.com> |
Mon, 10 Nov 2014 17:29:15 -0600 | |
changeset 23244 | 18cc87e4375a |
parent 23139 | e53f6b72a0e4 |
child 25981 | fa91c49a9b9f |
permissions | -rw-r--r-- |
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# tagmerge.py - merge .hgtags files |
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# |
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# Copyright 2014 Angel Ezquerra <angel.ezquerra@gmail.com> |
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# |
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# This software may be used and distributed according to the terms of the |
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# GNU General Public License version 2 or any later version. |
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|
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# This module implements an automatic merge algorithm for mercurial's tag files |
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# |
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# The tagmerge algorithm implemented in this module is able to resolve most |
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# merge conflicts that currently would trigger a .hgtags merge conflict. The |
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# only case that it does not (and cannot) handle is that in which two tags point |
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# to different revisions on each merge parent _and_ their corresponding tag |
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# histories have the same rank (i.e. the same length). In all other cases the |
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# merge algorithm will choose the revision belonging to the parent with the |
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# highest ranked tag history. The merged tag history is the combination of both |
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# tag histories (special care is taken to try to combine common tag histories |
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# where possible). |
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# |
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# In addition to actually merging the tags from two parents, taking into |
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# account the base, the algorithm also tries to minimize the difference |
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# between the merged tag file and the first parent's tag file (i.e. it tries to |
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# make the merged tag order as as similar as possible to the first parent's tag |
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# file order). |
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# |
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# The algorithm works as follows: |
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# 1. read the tags from p1, p2 and the base |
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# - when reading the p1 tags, also get the line numbers associated to each |
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# tag node (these will be used to sort the merged tags in a way that |
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# minimizes the diff to p1). Ignore the file numbers when reading p2 and |
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# the base |
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# 2. recover the "lost tags" (i.e. those that are found in the base but not on |
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# p1 or p2) and add them back to p1 and/or p2 |
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# - at this point the only tags that are on p1 but not on p2 are those new |
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# tags that were introduced in p1. Same thing for the tags that are on p2 |
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# but not on p2 |
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# 3. take all tags that are only on p1 or only on p2 (but not on the base) |
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# - Note that these are the tags that were introduced between base and p1 |
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# and between base and p2, possibly on separate clones |
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# 4. for each tag found both on p1 and p2 perform the following merge algorithm: |
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# - the tags conflict if their tag "histories" have the same "rank" (i.e. |
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# length) AND the last (current) tag is NOT the same |
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# - for non conflicting tags: |
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# - choose which are the high and the low ranking nodes |
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# - the high ranking list of nodes is the one that is longer. |
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# In case of draw favor p1 |
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# - the merged node list is made of 3 parts: |
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# - first the nodes that are common to the beginning of both |
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# the low and the high ranking nodes |
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# - second the non common low ranking nodes |
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# - finally the non common high ranking nodes (with the last |
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# one being the merged tag node) |
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# - note that this is equivalent to putting the whole low ranking |
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# node list first, followed by the non common high ranking nodes |
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# - note that during the merge we keep the "node line numbers", which will |
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# be used when writing the merged tags to the tag file |
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# 5. write the merged tags taking into account to their positions in the first |
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# parent (i.e. try to keep the relative ordering of the nodes that come |
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# from p1). This minimizes the diff between the merged and the p1 tag files |
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# This is done by using the following algorithm |
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# - group the nodes for a given tag that must be written next to each other |
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# - A: nodes that come from consecutive lines on p1 |
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# - B: nodes that come from p2 (i.e. whose associated line number is |
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# None) and are next to one of the a nodes in A |
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# - each group is associated with a line number coming from p1 |
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# - generate a "tag block" for each of the groups |
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# - a tag block is a set of consecutive "node tag" lines belonging to |
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# the same tag and which will be written next to each other on the |
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# merged tags file |
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# - sort the "tag blocks" according to their associated number line |
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# - put blocks whose nodes come all from p2 first |
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# - write the tag blocks in the sorted order |
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import tags as tagsmod |
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import util |
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from node import nullid, hex |
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from i18n import _ |
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import operator |
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hexnullid = hex(nullid) |
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def readtagsformerge(ui, repo, lines, fn='', keeplinenums=False): |
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'''read the .hgtags file into a structure that is suitable for merging |
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Depending on the keeplinenums flag, clear the line numbers associated |
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with each tag. This is done because only the line numbers of the first |
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parent are useful for merging. |
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''' |
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filetags = tagsmod._readtaghist(ui, repo, lines, fn=fn, recode=None, |
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calcnodelines=True)[1] |
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for tagname, taginfo in filetags.items(): |
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if not keeplinenums: |
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for el in taginfo: |
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el[1] = None |
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return filetags |
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def grouptagnodesbyline(tagnodes): |
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''' |
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Group nearby nodes (i.e. those that must be written next to each other) |
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The input is a list of [node, position] pairs, corresponding to a given tag |
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The position is the line number where the node was found on the first parent |
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.hgtags file, or None for those nodes that came from the base or the second |
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parent .hgtags files. |
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This function groups those [node, position] pairs, returning a list of |
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groups of nodes that must be written next to each other because their |
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positions are consecutive or have no position preference (because their |
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position is None). |
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The result is a list of [position, [consecutive node list]] |
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''' |
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firstlinenum = None |
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for hexnode, linenum in tagnodes: |
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firstlinenum = linenum |
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if firstlinenum is not None: |
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break |
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if firstlinenum is None: |
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return [[None, [el[0] for el in tagnodes]]] |
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tagnodes[0][1] = firstlinenum |
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groupednodes = [[firstlinenum, []]] |
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prevlinenum = firstlinenum |
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for hexnode, linenum in tagnodes: |
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if linenum is not None and linenum - prevlinenum > 1: |
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groupednodes.append([linenum, []]) |
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groupednodes[-1][1].append(hexnode) |
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if linenum is not None: |
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prevlinenum = linenum |
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return groupednodes |
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def writemergedtags(repo, mergedtags): |
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''' |
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write the merged tags while trying to minimize the diff to the first parent |
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133 |
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This function uses the ordering info stored on the merged tags dict to |
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generate an .hgtags file which is correct (in the sense that its contents |
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correspond to the result of the tag merge) while also being as close as |
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possible to the first parent's .hgtags file. |
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''' |
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# group the node-tag pairs that must be written next to each other |
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for tname, taglist in mergedtags.items(): |
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mergedtags[tname] = grouptagnodesbyline(taglist) |
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142 |
|
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# convert the grouped merged tags dict into a format that resembles the |
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# final .hgtags file (i.e. a list of blocks of 'node tag' pairs) |
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def taglist2string(tlist, tname): |
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return '\n'.join(['%s %s' % (hexnode, tname) for hexnode in tlist]) |
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147 |
|
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finaltags = [] |
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for tname, tags in mergedtags.items(): |
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for block in tags: |
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block[1] = taglist2string(block[1], tname) |
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finaltags += tags |
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153 |
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# the tag groups are linked to a "position" that can be used to sort them |
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# before writing them |
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# the position is calculated to ensure that the diff of the merged .hgtags |
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# file to the first parent's .hgtags file is as small as possible |
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158 |
finaltags.sort(key=operator.itemgetter(0)) |
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159 |
|
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# finally we can join the sorted groups to get the final contents of the |
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# merged .hgtags file, and then write it to disk |
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mergedtagstring = '\n'.join([tags for rank, tags in finaltags if tags]) |
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fp = repo.wfile('.hgtags', 'wb') |
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fp.write(mergedtagstring + '\n') |
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165 |
fp.close() |
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166 |
|
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167 |
def singletagmerge(p1nodes, p2nodes): |
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168 |
''' |
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merge the nodes corresponding to a single tag |
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170 |
|
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171 |
Note that the inputs are lists of node-linenum pairs (i.e. not just lists |
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172 |
of nodes) |
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173 |
''' |
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174 |
if not p2nodes: |
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175 |
return p1nodes |
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176 |
if not p1nodes: |
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177 |
return p2nodes |
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178 |
|
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# there is no conflict unless both tags point to different revisions |
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# and have a non identical tag history |
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181 |
p1currentnode = p1nodes[-1][0] |
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p2currentnode = p2nodes[-1][0] |
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183 |
if p1currentnode != p2currentnode and len(p1nodes) == len(p2nodes): |
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184 |
# cannot merge two tags with same rank pointing to different nodes |
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185 |
return None |
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186 |
|
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187 |
# which are the highest ranking (hr) / lowest ranking (lr) nodes? |
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188 |
if len(p1nodes) >= len(p2nodes): |
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189 |
hrnodes, lrnodes = p1nodes, p2nodes |
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190 |
else: |
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191 |
hrnodes, lrnodes = p2nodes, p1nodes |
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192 |
|
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193 |
# the lowest ranking nodes will be written first, followed by the highest |
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194 |
# ranking nodes |
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195 |
# to avoid unwanted tag rank explosion we try to see if there are some |
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196 |
# common nodes that can be written only once |
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197 |
commonidx = len(lrnodes) |
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198 |
for n in range(len(lrnodes)): |
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199 |
if hrnodes[n][0] != lrnodes[n][0]: |
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200 |
commonidx = n |
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201 |
break |
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202 |
lrnodes[n][1] = p1nodes[n][1] |
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203 |
|
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204 |
# the merged node list has 3 parts: |
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205 |
# - common nodes |
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206 |
# - non common lowest ranking nodes |
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207 |
# - non common highest ranking nodes |
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208 |
# note that the common nodes plus the non common lowest ranking nodes is the |
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209 |
# whole list of lr nodes |
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210 |
return lrnodes + hrnodes[commonidx:] |
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211 |
|
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212 |
def merge(repo, fcd, fco, fca): |
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213 |
''' |
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214 |
Merge the tags of two revisions, taking into account the base tags |
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215 |
Try to minimize the diff between the merged tags and the first parent tags |
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216 |
''' |
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217 |
ui = repo.ui |
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218 |
# read the p1, p2 and base tags |
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219 |
# only keep the line numbers for the p1 tags |
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220 |
p1tags = readtagsformerge( |
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221 |
ui, repo, fcd.data().splitlines(), fn="p1 tags", |
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222 |
keeplinenums=True) |
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223 |
p2tags = readtagsformerge( |
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224 |
ui, repo, fco.data().splitlines(), fn="p2 tags", |
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225 |
keeplinenums=False) |
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226 |
basetags = readtagsformerge( |
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227 |
ui, repo, fca.data().splitlines(), fn="base tags", |
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228 |
keeplinenums=False) |
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229 |
|
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230 |
# recover the list of "lost tags" (i.e. those that were found on the base |
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# revision but not on one of the revisions being merged) |
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232 |
basetagset = set(basetags) |
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233 |
for n, pntags in enumerate((p1tags, p2tags)): |
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pntagset = set(pntags) |
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pnlosttagset = basetagset - pntagset |
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236 |
for t in pnlosttagset: |
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pntags[t] = basetags[t] |
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if pntags[t][-1][0] != hexnullid: |
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pntags[t].append([hexnullid, None]) |
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240 |
|
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conflictedtags = [] # for reporting purposes |
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mergedtags = util.sortdict(p1tags) |
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# sortdict does not implement iteritems() |
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for tname, p2nodes in p2tags.items(): |
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if tname not in mergedtags: |
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mergedtags[tname] = p2nodes |
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247 |
continue |
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p1nodes = mergedtags[tname] |
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mergednodes = singletagmerge(p1nodes, p2nodes) |
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250 |
if mergednodes is None: |
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conflictedtags.append(tname) |
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252 |
continue |
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mergedtags[tname] = mergednodes |
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254 |
|
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255 |
if conflictedtags: |
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256 |
numconflicts = len(conflictedtags) |
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257 |
ui.warn(_('automatic .hgtags merge failed\n' |
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258 |
'the following %d tags are in conflict: %s\n') |
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259 |
% (numconflicts, ', '.join(sorted(conflictedtags)))) |
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260 |
return True, 1 |
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261 |
|
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262 |
writemergedtags(repo, mergedtags) |
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263 |
ui.note(_('.hgtags merged successfully\n')) |
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264 |
return False, 0 |
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parents:
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265 |