Test that the syntax of "unified tests" is properly processed
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Simple commands:
$ echo foo
foo
$ printf 'oh no'
oh no (no-eol)
$ printf 'bar\nbaz\n' | cat
bar
baz
Multi-line command:
$ foo() {
> echo bar
> }
$ foo
bar
Return codes before inline python:
$ sh -c 'exit 1'
[1]
Doctest commands:
>>> from __future__ import print_function
>>> print('foo')
foo
$ echo interleaved
interleaved
>>> for c in 'xyz':
... print(c)
x
y
z
>>> print()
>>> foo = 'global name'
>>> def func():
... print(foo, 'should be visible in func()')
>>> func()
global name should be visible in func()
>>> print('''multiline
... string''')
multiline
string
Regular expressions:
$ echo foobarbaz
foobar.* (re)
$ echo barbazquux
.*quux.* (re)
Globs:
$ printf '* \\foobarbaz {10}\n'
\* \\fo?bar* {10} (glob)
Literal match ending in " (re)":
$ echo 'foo (re)'
foo (re)
Windows: \r\n is handled like \n and can be escaped:
#if windows
$ printf 'crlf\r\ncr\r\tcrlf\r\ncrlf\r\n'
crlf
cr\r (no-eol) (esc)
\tcrlf (esc)
crlf\r (esc)
#endif
Combining esc with other markups - and handling lines ending with \r instead of \n:
$ printf 'foo/bar\r'
fo?/bar\r (no-eol) (glob) (esc)
#if windows
$ printf 'foo\\bar\r'
foo/bar\r (no-eol) (glob) (esc)
#endif
$ printf 'foo/bar\rfoo/bar\r'
foo.bar\r \(no-eol\) (re) (esc)
foo.bar\r \(no-eol\) (re)
testing hghave
$ hghave true
$ hghave false
skipped: missing feature: nail clipper
[1]
$ hghave no-true
skipped: system supports yak shaving
[1]
$ hghave no-false
Conditional sections based on hghave:
#if true
$ echo tested
tested
#else
$ echo skipped
#endif
#if false
$ echo skipped
#else
$ echo tested
tested
#endif
#if no-false
$ echo tested
tested
#else
$ echo skipped
#endif
#if no-true
$ echo skipped
#else
$ echo tested
tested
#endif
Exit code:
$ (exit 1)
[1]