backout: use commonancestorsheads for checking linear heritage
If two revisions are linearly related, there will only be one ancestor, and
commonancestors and commonancestorsheads would give the same result.
commonancestorsheads is however slightly simpler, faster and more correct.
$ check_code="$TESTDIR"/../contrib/check-code.py
$ cd "$TESTDIR"/..
$ if hg identify -q > /dev/null 2>&1; then :
> else
> echo "skipped: not a Mercurial working dir" >&2
> exit 80
> fi
Prepare check for Python files without py extension
$ cp \
> hg \
> hgweb.cgi \
> contrib/convert-repo \
> contrib/dumprevlog \
> contrib/hgweb.fcgi \
> contrib/hgweb.wsgi \
> contrib/simplemerge \
> contrib/undumprevlog \
> i18n/hggettext \
> i18n/posplit \
> tests/hghave \
> tests/dummyssh \
> "$TESTTMP"/
$ for f in "$TESTTMP"/*; do mv "$f" "$f.py"; done
New errors are not allowed. Warnings are strongly discouraged.
(The writing "no-che?k-code" is for not skipping this file when checking.)
$ { hg manifest 2>/dev/null; ls "$TESTTMP"/*.py | sed 's-\\-/-g'; } |
> xargs "$check_code" --warnings --per-file=0 || false
Skipping hgext/zeroconf/Zeroconf.py it has no-che?k-code (glob)
Skipping i18n/polib.py it has no-che?k-code (glob)
Skipping mercurial/httpclient/__init__.py it has no-che?k-code (glob)
Skipping mercurial/httpclient/_readers.py it has no-che?k-code (glob)
Skipping mercurial/httpclient/socketutil.py it has no-che?k-code (glob)