backout: use commonancestorsheads for checking linear heritage
If two revisions are linearly related, there will only be one ancestor, and
commonancestors and commonancestorsheads would give the same result.
commonancestorsheads is however slightly simpler, faster and more correct.
# this is hack to make sure no escape characters are inserted into the output
import os, sys
if 'TERM' in os.environ:
del os.environ['TERM']
import doctest
def testmod(name, optionflags=0, testtarget=None):
__import__(name)
mod = sys.modules[name]
if testtarget is not None:
mod = getattr(mod, testtarget)
doctest.testmod(mod, optionflags=optionflags)
testmod('mercurial.changelog')
testmod('mercurial.dagparser', optionflags=doctest.NORMALIZE_WHITESPACE)
testmod('mercurial.dispatch')
testmod('mercurial.encoding')
testmod('mercurial.hg')
testmod('mercurial.hgweb.hgwebdir_mod')
testmod('mercurial.match')
testmod('mercurial.minirst')
testmod('mercurial.revset')
testmod('mercurial.store')
testmod('mercurial.subrepo')
testmod('mercurial.templatefilters')
testmod('mercurial.ui')
testmod('mercurial.url')
testmod('mercurial.util')
testmod('mercurial.util', testtarget='platform')
testmod('hgext.convert.cvsps')
testmod('hgext.convert.filemap')
testmod('hgext.convert.subversion')