view tests/test-context.py @ 18987:3605d4e7e618

revlog: choose a consistent ancestor when there's a tie Previously, we chose a rev based on numeric ordering, which could cause "the same merge" in topologically identical but numerically different repos to choose different merge bases. We now choose the lexically least node; this is stable across different revlog orderings.
author Bryan O'Sullivan <bryano@fb.com>
date Tue, 16 Apr 2013 10:08:19 -0700
parents bd23d5f28bbb
children 503bb3af70fe
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import os
from mercurial import hg, ui, context, encoding

u = ui.ui()

repo = hg.repository(u, 'test1', create=1)
os.chdir('test1')

# create 'foo' with fixed time stamp
f = open('foo', 'w')
f.write('foo\n')
f.close()
os.utime('foo', (1000, 1000))

# add+commit 'foo'
repo[None].add(['foo'])
repo.commit(text='commit1', date="0 0")

print "workingfilectx.date =", repo[None]['foo'].date()

# test memctx with non-ASCII commit message

def filectxfn(repo, memctx, path):
    return context.memfilectx("foo", "")

ctx = context.memctx(repo, ['tip', None],
                     encoding.tolocal("Gr\xc3\xbcezi!"),
                     ["foo"], filectxfn)
ctx.commit()
for enc in "ASCII", "Latin-1", "UTF-8":
    encoding.encoding = enc
    print "%-8s: %s" % (enc, repo["tip"].description())