tests: add -k to test scripts matching keywords
argument is a space-separated list of keywords that are searched for
in the name and body of each test. This makes it easy to run only
tests related to tags, hgweb, revert, etc. (eg -k "tag hgweb revert").
# Mercurial extension to make it easy to refer to the parent of a revision
#
# Copyright (C) 2007 Alexis S. L. Carvalho <alexis@cecm.usp.br>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2, incorporated herein by reference.
'''interpret suffixes to refer to ancestor revisions
This extension allows you to use git-style suffixes to refer to the
ancestors of a specific revision.
For example, if you can refer to a revision as "foo", then::
foo^N = Nth parent of foo
foo^0 = foo
foo^1 = first parent of foo
foo^2 = second parent of foo
foo^ = foo^1
foo~N = Nth first grandparent of foo
foo~0 = foo
foo~1 = foo^1 = foo^ = first parent of foo
foo~2 = foo^1^1 = foo^^ = first parent of first parent of foo
'''
from mercurial import error
def reposetup(ui, repo):
if not repo.local():
return
class parentrevspecrepo(repo.__class__):
def lookup(self, key):
try:
_super = super(parentrevspecrepo, self)
return _super.lookup(key)
except error.RepoError:
pass
circ = key.find('^')
tilde = key.find('~')
if circ < 0 and tilde < 0:
raise
elif circ >= 0 and tilde >= 0:
end = min(circ, tilde)
else:
end = max(circ, tilde)
cl = self.changelog
base = key[:end]
try:
node = _super.lookup(base)
except error.RepoError:
# eek - reraise the first error
return _super.lookup(key)
rev = cl.rev(node)
suffix = key[end:]
i = 0
while i < len(suffix):
# foo^N => Nth parent of foo
# foo^0 == foo
# foo^1 == foo^ == 1st parent of foo
# foo^2 == 2nd parent of foo
if suffix[i] == '^':
j = i + 1
p = cl.parentrevs(rev)
if j < len(suffix) and suffix[j].isdigit():
j += 1
n = int(suffix[i+1:j])
if n > 2 or n == 2 and p[1] == -1:
raise
else:
n = 1
if n:
rev = p[n - 1]
i = j
# foo~N => Nth first grandparent of foo
# foo~0 = foo
# foo~1 = foo^1 == foo^ == 1st parent of foo
# foo~2 = foo^1^1 == foo^^ == 1st parent of 1st parent of foo
elif suffix[i] == '~':
j = i + 1
while j < len(suffix) and suffix[j].isdigit():
j += 1
if j == i + 1:
raise
n = int(suffix[i+1:j])
for k in xrange(n):
rev = cl.parentrevs(rev)[0]
i = j
else:
raise
return cl.node(rev)
repo.__class__ = parentrevspecrepo