subrepo: process merge substate in sorted order in submerge()
This ensures that subrepositories are pulled in a well defined
order when cloning the parent repository.
BEFORE:
$ hg clone http://hg.gerg.ca/allextensions
destination directory: allextensions
requesting all changes
adding changesets
adding manifests
adding file changes
added 10 changesets with 20 changes to 6 files
updating to branch default
pulling subrepo caseguard from http://bitbucket.org/alexandru/caseguard
real URL is https://bitbucket.org/alexandru/caseguard
requesting all changes
adding changesets
adding manifests
adding file changes
added 81 changesets with 100 changes to 13 files
pulling subrepo hg-prompt from http://bitbucket.org/sjl/hg-prompt
real URL is https://bitbucket.org/sjl/hg-prompt
requesting all changes
adding changesets
adding manifests
adding file changes
added 114 changesets with 176 changes to 35 files
pulling subrepo hgpaste from http://bitbucket.org/birkenfeld/hgpaste
real URL is https://bitbucket.org/birkenfeld/hgpaste
requesting all changes
adding changesets
adding manifests
adding file changes
added 18 changesets with 18 changes to 2 files
...
AFTER:
$ hg clone http://hg.gerg.ca/allextensions
destination directory: allextensions
requesting all changes
adding changesets
adding manifests
adding file changes
added 10 changesets with 20 changes to 6 files
updating to branch default
pulling subrepo Artemis from http://hg.mrzv.org/Artemis
requesting all changes
adding changesets
adding manifests
adding file changes
added 55 changesets with 108 changes to 47 files
...
# ancestor.py - generic DAG ancestor algorithm for mercurial
#
# Copyright 2006 Matt Mackall <mpm@selenic.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
import heapq
def ancestor(a, b, pfunc):
"""
Returns the common ancestor of a and b that is furthest from a
root (as measured by longest path) or None if no ancestor is
found. If there are multiple common ancestors at the same
distance, the first one found is returned.
pfunc must return a list of parent vertices for a given vertex
"""
if a == b:
return a
a, b = sorted([a, b])
# find depth from root of all ancestors
# depth is stored as a negative for heapq
parentcache = {}
visit = [a, b]
depth = {}
while visit:
vertex = visit[-1]
pl = pfunc(vertex)
parentcache[vertex] = pl
if not pl:
depth[vertex] = 0
visit.pop()
else:
for p in pl:
if p == a or p == b: # did we find a or b as a parent?
return p # we're done
if p not in depth:
visit.append(p)
if visit[-1] == vertex:
# -(maximum distance of parents + 1)
depth[vertex] = min([depth[p] for p in pl]) - 1
visit.pop()
# traverse ancestors in order of decreasing distance from root
def ancestors(vertex):
h = [(depth[vertex], vertex)]
seen = set()
while h:
d, n = heapq.heappop(h)
if n not in seen:
seen.add(n)
yield (d, n)
for p in parentcache[n]:
heapq.heappush(h, (depth[p], p))
def generations(vertex):
sg, s = None, set()
for g, v in ancestors(vertex):
if g != sg:
if sg:
yield sg, s
sg, s = g, set((v,))
else:
s.add(v)
yield sg, s
x = generations(a)
y = generations(b)
gx = x.next()
gy = y.next()
# increment each ancestor list until it is closer to root than
# the other, or they match
try:
while 1:
if gx[0] == gy[0]:
for v in gx[1]:
if v in gy[1]:
return v
gy = y.next()
gx = x.next()
elif gx[0] > gy[0]:
gy = y.next()
else:
gx = x.next()
except StopIteration:
return None