ancestor: optimize _lazyancestorsiter() for contiguous chains
If there's no revision between p1 and current, p1 must be the next revision
to visit. In this case, we can get around the overhead of heappop/push
operations. Note that this is faster than using heapreplace().
'current - p1 == 1' could be generalized as 'all(r not in seen for r in
xrange(p1, current)', but Python is too slow to do such thing.
#require docutils gettext
$ $TESTDIR/check-gendoc pt_BR
checking for parse errors