mercurial/strutil.py
author Gregory Szorc <gregory.szorc@gmail.com>
Thu, 24 Jul 2014 12:12:12 -0700
branchstable
changeset 21939 f486001f9d6f
parent 10263 25e572394f5c
child 25979 b723f05ec49b
permissions -rw-r--r--
revset: optimize baseset.__sub__ (issue4313) dd716807fd23 regressed performance of baseset.__sub__ by introducing a lazyset. This patch restores that lost performance by eagerly evaluating baseset.__sub__ if the other set is a baseset. revsetbenchmark.py results impacted by this change: revset #6: roots(0::tip) 0) wall 2.923473 comb 2.920000 user 2.920000 sys 0.000000 (best of 4) 1) wall 0.077614 comb 0.080000 user 0.080000 sys 0.000000 (best of 100) revset #23: roots((0:tip)::) 0) wall 2.875178 comb 2.880000 user 2.880000 sys 0.000000 (best of 4) 1) wall 0.154519 comb 0.150000 user 0.150000 sys 0.000000 (best of 61) On the author's machine, this slowdown manifested during evaluation of 'roots(%ln::)' in phases.retractboundary after unbundling the Firefox repository. Using `time hg unbundle firefox.hg` as a benchmark: Before: 8:00 After: 4:28 Delta: -3:32 For reference, the subset and cs baseset instances impacted by this change were of lengths 193634 and 193627, respectively. Explicit test coverage of roots(%ln::), while similar to the existing roots(0::tip) benchmark, has been added.

# strutil.py - string utilities for Mercurial
#
# Copyright 2006 Vadim Gelfer <vadim.gelfer@gmail.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.

def findall(haystack, needle, start=0, end=None):
    if end is None:
        end = len(haystack)
    if end < 0:
        end += len(haystack)
    if start < 0:
        start += len(haystack)
    while start < end:
        c = haystack.find(needle, start, end)
        if c == -1:
            break
        yield c
        start = c + 1

def rfindall(haystack, needle, start=0, end=None):
    if end is None:
        end = len(haystack)
    if end < 0:
        end += len(haystack)
    if start < 0:
        start += len(haystack)
    while end >= 0:
        c = haystack.rfind(needle, start, end)
        if c == -1:
            break
        yield c
        end = c - 1