resourceutil: implement `is_resource()`
This will be needed when iterating resources.
Differential Revision: https://phab.mercurial-scm.org/D7773
--- a/mercurial/utils/resourceutil.py Sat Dec 28 23:35:13 2019 -0500
+++ b/mercurial/utils/resourceutil.py Sun Dec 29 20:32:56 2019 -0500
@@ -40,6 +40,8 @@
try:
from importlib import resources
+ from .. import encoding
+
# Force loading of the resources module
resources.open_binary # pytype: disable=module-attr
@@ -48,6 +50,11 @@
pycompat.sysstr(package), pycompat.sysstr(name)
)
+ def is_resource(package, name):
+ return resources.is_resource(
+ pycompat.sysstr(package), encoding.strfromlocal(name)
+ )
+
except (ImportError, AttributeError):
@@ -57,3 +64,11 @@
def open_resource(package, name):
path = os.path.join(_package_path(package), name)
return open(path, 'rb')
+
+ def is_resource(package, name):
+ path = os.path.join(_package_path(package), name)
+
+ try:
+ return os.path.isfile(pycompat.fsdecode(path))
+ except (IOError, OSError):
+ return False