author | Siddharth Agarwal <sid0@fb.com> |
Wed, 28 Nov 2012 10:35:12 -0800 | |
changeset 17976 | 09d5681d5b72 |
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# ancestor.py - generic DAG ancestor algorithm for mercurial |
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# |
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# Copyright 2006 Matt Mackall <mpm@selenic.com> |
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# |
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# This software may be used and distributed according to the terms of the |
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# GNU General Public License version 2 or any later version. |
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import heapq |
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from node import nullrev |
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def ancestor(a, b, pfunc): |
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""" |
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Returns the common ancestor of a and b that is furthest from a |
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root (as measured by longest path) or None if no ancestor is |
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found. If there are multiple common ancestors at the same |
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distance, the first one found is returned. |
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pfunc must return a list of parent vertices for a given vertex |
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""" |
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if a == b: |
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return a |
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a, b = sorted([a, b]) |
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# find depth from root of all ancestors |
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# depth is stored as a negative for heapq |
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parentcache = {} |
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visit = [a, b] |
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depth = {} |
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while visit: |
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vertex = visit[-1] |
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pl = pfunc(vertex) |
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parentcache[vertex] = pl |
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if not pl: |
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depth[vertex] = 0 |
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visit.pop() |
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else: |
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for p in pl: |
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if p == a or p == b: # did we find a or b as a parent? |
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return p # we're done |
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if p not in depth: |
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visit.append(p) |
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if visit[-1] == vertex: |
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# -(maximum distance of parents + 1) |
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depth[vertex] = min([depth[p] for p in pl]) - 1 |
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visit.pop() |
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# traverse ancestors in order of decreasing distance from root |
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def ancestors(vertex): |
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h = [(depth[vertex], vertex)] |
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seen = set() |
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while h: |
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d, n = heapq.heappop(h) |
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if n not in seen: |
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seen.add(n) |
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yield (d, n) |
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for p in parentcache[n]: |
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heapq.heappush(h, (depth[p], p)) |
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def generations(vertex): |
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sg, s = None, set() |
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for g, v in ancestors(vertex): |
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if g != sg: |
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if sg: |
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yield sg, s |
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sg, s = g, set((v,)) |
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else: |
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s.add(v) |
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yield sg, s |
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x = generations(a) |
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y = generations(b) |
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gx = x.next() |
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gy = y.next() |
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# increment each ancestor list until it is closer to root than |
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# the other, or they match |
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try: |
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while True: |
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if gx[0] == gy[0]: |
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for v in gx[1]: |
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if v in gy[1]: |
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return v |
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gy = y.next() |
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gx = x.next() |
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elif gx[0] > gy[0]: |
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gy = y.next() |
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else: |
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gx = x.next() |
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except StopIteration: |
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return None |
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def missingancestors(revs, bases, pfunc): |
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"""Return all the ancestors of revs that are not ancestors of bases. |
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This may include elements from revs. |
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Equivalent to the revset (::revs - ::bases). Revs are returned in |
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revision number order, which is a topological order. |
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revs and bases should both be iterables. pfunc must return a list of |
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parent revs for a given revs. |
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graph is a dict of child->parent adjacency lists for this graph: |
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| | |
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| o 2 |
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|/ |
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o 1 |
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| |
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o 0 |
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>>> graph = {0: [-1], 1: [0], 2: [1], 3: [1], 4: [2], 5: [4], 6: [4], |
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... 7: [4], 8: [-1], 9: [6, 7], 10: [5], 11: [3, 7], 12: [9], |
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... 13: [8]} |
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>>> pfunc = graph.get |
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Empty revs |
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>>> missingancestors([], [1], pfunc) |
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[] |
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>>> missingancestors([], [], pfunc) |
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[] |
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|
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If bases is empty, it's the same as if it were [nullrev] |
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>>> missingancestors([12], [], pfunc) |
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[0, 1, 2, 4, 6, 7, 9, 12] |
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|
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Trivial case: revs == bases |
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>>> missingancestors([0], [0], pfunc) |
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[] |
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>>> missingancestors([4, 5, 6], [6, 5, 4], pfunc) |
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[] |
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|
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With nullrev |
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>>> missingancestors([-1], [12], pfunc) |
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[] |
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>>> missingancestors([12], [-1], pfunc) |
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[0, 1, 2, 4, 6, 7, 9, 12] |
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|
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9 is a parent of 12. 7 is a parent of 9, so an ancestor of 12. 6 is an |
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ancestor of 12 but not of 7. |
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>>> missingancestors([12], [9], pfunc) |
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[12] |
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>>> missingancestors([9], [12], pfunc) |
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[] |
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>>> missingancestors([12, 9], [7], pfunc) |
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[6, 9, 12] |
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>>> missingancestors([7, 6], [12], pfunc) |
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[] |
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|
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More complex cases |
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>>> missingancestors([10], [11, 12], pfunc) |
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[5, 10] |
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>>> missingancestors([11], [10], pfunc) |
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[3, 7, 11] |
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>>> missingancestors([11], [10, 12], pfunc) |
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[3, 11] |
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>>> missingancestors([12], [10], pfunc) |
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[6, 7, 9, 12] |
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>>> missingancestors([12], [11], pfunc) |
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[6, 9, 12] |
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>>> missingancestors([10, 11, 12], [13], pfunc) |
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[0, 1, 2, 3, 4, 5, 6, 7, 9, 10, 11, 12] |
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>>> missingancestors([13], [10, 11, 12], pfunc) |
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[8, 13] |
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""" |
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|
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revsvisit = set(revs) |
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basesvisit = set(bases) |
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if not revsvisit: |
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191 |
return [] |
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if not basesvisit: |
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basesvisit.add(nullrev) |
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start = max(max(revsvisit), max(basesvisit)) |
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bothvisit = revsvisit.intersection(basesvisit) |
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revsvisit.difference_update(bothvisit) |
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basesvisit.difference_update(bothvisit) |
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# At this point, we hold the invariants that: |
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# - revsvisit is the set of nodes we know are an ancestor of at least one |
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# of the nodes in revs |
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# - basesvisit is the same for bases |
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# - bothvisit is the set of nodes we know are ancestors of at least one of |
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# the nodes in revs and one of the nodes in bases |
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# - a node may be in none or one, but not more, of revsvisit, basesvisit |
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# and bothvisit at any given time |
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# Now we walk down in reverse topo order, adding parents of nodes already |
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# visited to the sets while maintaining the invariants. When a node is |
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# found in both revsvisit and basesvisit, it is removed from them and |
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# added to bothvisit instead. When revsvisit becomes empty, there are no |
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# more ancestors of revs that aren't also ancestors of bases, so exit. |
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211 |
|
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missing = [] |
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for curr in xrange(start, nullrev, -1): |
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if not revsvisit: |
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break |
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|
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if curr in bothvisit: |
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bothvisit.remove(curr) |
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# curr's parents might have made it into revsvisit or basesvisit |
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# through another path |
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for p in pfunc(curr): |
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222 |
revsvisit.discard(p) |
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basesvisit.discard(p) |
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bothvisit.add(p) |
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continue |
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226 |
|
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227 |
# curr will never be in both revsvisit and basesvisit, since if it |
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# were it'd have been pushed to bothvisit |
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229 |
if curr in revsvisit: |
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missing.append(curr) |
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thisvisit = revsvisit |
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othervisit = basesvisit |
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elif curr in basesvisit: |
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thisvisit = basesvisit |
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othervisit = revsvisit |
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236 |
else: |
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# not an ancestor of revs or bases: ignore |
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238 |
continue |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
14494
diff
changeset
|
239 |
|
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
14494
diff
changeset
|
240 |
thisvisit.remove(curr) |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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diff
changeset
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241 |
for p in pfunc(curr): |
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ancestor: faster algorithm for difference of ancestor sets
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parents:
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242 |
if p == nullrev: |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
14494
diff
changeset
|
243 |
pass |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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diff
changeset
|
244 |
elif p in othervisit or p in bothvisit: |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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diff
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245 |
# p is implicitly in thisvisit. This means p is or should be |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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diff
changeset
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246 |
# in bothvisit |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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247 |
revsvisit.discard(p) |
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Siddharth Agarwal <sid0@fb.com>
parents:
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248 |
basesvisit.discard(p) |
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parents:
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249 |
bothvisit.add(p) |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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diff
changeset
|
250 |
else: |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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diff
changeset
|
251 |
# visit later |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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252 |
thisvisit.add(p) |
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
14494
diff
changeset
|
253 |
|
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ancestor: faster algorithm for difference of ancestor sets
Siddharth Agarwal <sid0@fb.com>
parents:
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diff
changeset
|
254 |
missing.reverse() |
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parents:
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diff
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|
255 |
return missing |