mercurial/ancestor.py
author Wagner Bruna <wbruna@softwareexpress.com.br>
Mon, 22 Jun 2009 15:58:21 -0300
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# ancestor.py - generic DAG ancestor algorithm for mercurial
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#
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# Copyright 2006 Matt Mackall <mpm@selenic.com>
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#
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# This software may be used and distributed according to the terms of the
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# GNU General Public License version 2, incorporated herein by reference.
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import heapq
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def ancestor(a, b, pfunc):
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    """
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    return the least common ancestor of nodes a and b or None if there
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    is no such ancestor.
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    pfunc must return a list of parent vertices
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    """
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    if a == b:
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        return a
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    # find depth from root of all ancestors
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    parentcache = {}
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    visit = [a, b]
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    depth = {}
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    while visit:
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        vertex = visit[-1]
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        pl = pfunc(vertex)
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        parentcache[vertex] = pl
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        if not pl:
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            depth[vertex] = 0
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            visit.pop()
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        else:
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            for p in pl:
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                if p == a or p == b: # did we find a or b as a parent?
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                    return p # we're done
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                if p not in depth:
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                    visit.append(p)
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            if visit[-1] == vertex:
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                depth[vertex] = min([depth[p] for p in pl]) - 1
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                visit.pop()
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    # traverse ancestors in order of decreasing distance from root
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    def ancestors(vertex):
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        h = [(depth[vertex], vertex)]
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        seen = set()
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        while h:
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            d, n = heapq.heappop(h)
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            if n not in seen:
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                seen.add(n)
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                yield (d, n)
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                for p in parentcache[n]:
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                    heapq.heappush(h, (depth[p], p))
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    def generations(vertex):
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        sg, s = None, set()
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        for g, v in ancestors(vertex):
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            if g != sg:
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                if sg:
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                    yield sg, s
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                sg, s = g, set((v,))
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            else:
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                s.add(v)
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        yield sg, s
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    x = generations(a)
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    y = generations(b)
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    gx = x.next()
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    gy = y.next()
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    # increment each ancestor list until it is closer to root than
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    # the other, or they match
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    try:
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        while 1:
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            if gx[0] == gy[0]:
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                for v in gx[1]:
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                    if v in gy[1]:
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                        return v
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                gy = y.next()
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                gx = x.next()
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            elif gx[0] > gy[0]:
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                gy = y.next()
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            else:
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                gx = x.next()
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    except StopIteration:
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        return None