annotate mercurial/ancestor.py @ 11044:5ab414f71e87

keyword: remove mq commands from restricted list Monkeypatching patch.diff takes care of this since 911f5be5d159. Test mq more thoroughly by loosening [keywordmaps] and comparing the output of hg cat with keyword expansion enabled and disabled.
author Christian Ebert <blacktrash@gmx.net>
date Mon, 26 Apr 2010 03:54:18 +0200
parents d6512b3e9ac0
children 67bb9d78f05e
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1 # ancestor.py - generic DAG ancestor algorithm for mercurial
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2 #
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3 # Copyright 2006 Matt Mackall <mpm@selenic.com>
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4 #
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5 # This software may be used and distributed according to the terms of the
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6 # GNU General Public License version 2 or any later version.
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7
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8 import heapq
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9
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10 def ancestor(a, b, pfunc):
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11 """
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12 return a minimal-distance ancestor of nodes a and b, or None if there is no
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13 such ancestor. Note that there can be several ancestors with the same
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14 (minimal) distance, and the one returned is arbitrary.
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15
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16 pfunc must return a list of parent vertices for a given vertex
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17 """
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18
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19 if a == b:
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20 return a
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21
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22 # find depth from root of all ancestors
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23 parentcache = {}
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24 visit = [a, b]
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25 depth = {}
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26 while visit:
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27 vertex = visit[-1]
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28 pl = pfunc(vertex)
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29 parentcache[vertex] = pl
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30 if not pl:
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31 depth[vertex] = 0
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32 visit.pop()
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33 else:
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34 for p in pl:
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35 if p == a or p == b: # did we find a or b as a parent?
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36 return p # we're done
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37 if p not in depth:
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38 visit.append(p)
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39 if visit[-1] == vertex:
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40 depth[vertex] = min([depth[p] for p in pl]) - 1
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41 visit.pop()
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42
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43 # traverse ancestors in order of decreasing distance from root
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44 def ancestors(vertex):
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45 h = [(depth[vertex], vertex)]
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46 seen = set()
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47 while h:
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48 d, n = heapq.heappop(h)
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49 if n not in seen:
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50 seen.add(n)
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51 yield (d, n)
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52 for p in parentcache[n]:
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53 heapq.heappush(h, (depth[p], p))
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54
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55 def generations(vertex):
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56 sg, s = None, set()
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57 for g, v in ancestors(vertex):
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58 if g != sg:
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59 if sg:
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60 yield sg, s
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61 sg, s = g, set((v,))
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62 else:
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63 s.add(v)
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64 yield sg, s
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65
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66 x = generations(a)
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67 y = generations(b)
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68 gx = x.next()
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69 gy = y.next()
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70
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71 # increment each ancestor list until it is closer to root than
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72 # the other, or they match
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73 try:
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74 while 1:
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75 if gx[0] == gy[0]:
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76 for v in gx[1]:
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77 if v in gy[1]:
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78 return v
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79 gy = y.next()
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80 gx = x.next()
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81 elif gx[0] > gy[0]:
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82 gy = y.next()
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83 else:
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84 gx = x.next()
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85 except StopIteration:
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86 return None