author | Augie Fackler <durin42@gmail.com> |
Thu, 12 May 2011 10:48:31 -0500 | |
changeset 14341 | 5c3de67e7402 |
parent 13554 | 22565ddb28e7 |
child 14494 | 1ffeeb91c55d |
permissions | -rw-r--r-- |
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# ancestor.py - generic DAG ancestor algorithm for mercurial |
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# |
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# Copyright 2006 Matt Mackall <mpm@selenic.com> |
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# |
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# This software may be used and distributed according to the terms of the |
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# GNU General Public License version 2 or any later version. |
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import heapq |
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def ancestor(a, b, pfunc): |
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""" |
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Returns the common ancestor of a and b that is furthest from a |
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root (as measured by longest path) or None if no ancestor is |
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found. If there are multiple common ancestors at the same |
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distance, the first one found is returned. |
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pfunc must return a list of parent vertices for a given vertex |
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""" |
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if a == b: |
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return a |
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a, b = sorted([a, b]) |
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# find depth from root of all ancestors |
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# depth is stored as a negative for heapq |
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parentcache = {} |
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visit = [a, b] |
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depth = {} |
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while visit: |
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vertex = visit[-1] |
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pl = pfunc(vertex) |
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parentcache[vertex] = pl |
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if not pl: |
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depth[vertex] = 0 |
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visit.pop() |
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else: |
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for p in pl: |
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if p == a or p == b: # did we find a or b as a parent? |
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return p # we're done |
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if p not in depth: |
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visit.append(p) |
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if visit[-1] == vertex: |
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# -(maximum distance of parents + 1) |
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depth[vertex] = min([depth[p] for p in pl]) - 1 |
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visit.pop() |
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# traverse ancestors in order of decreasing distance from root |
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def ancestors(vertex): |
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h = [(depth[vertex], vertex)] |
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seen = set() |
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while h: |
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d, n = heapq.heappop(h) |
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if n not in seen: |
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seen.add(n) |
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yield (d, n) |
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for p in parentcache[n]: |
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heapq.heappush(h, (depth[p], p)) |
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def generations(vertex): |
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sg, s = None, set() |
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for g, v in ancestors(vertex): |
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if g != sg: |
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if sg: |
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yield sg, s |
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sg, s = g, set((v,)) |
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else: |
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s.add(v) |
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yield sg, s |
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x = generations(a) |
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y = generations(b) |
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gx = x.next() |
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gy = y.next() |
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# increment each ancestor list until it is closer to root than |
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# the other, or they match |
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try: |
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while 1: |
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if gx[0] == gy[0]: |
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for v in gx[1]: |
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if v in gy[1]: |
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return v |
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gy = y.next() |
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gx = x.next() |
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elif gx[0] > gy[0]: |
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gy = y.next() |
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else: |
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gx = x.next() |
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except StopIteration: |
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return None |