Mercurial > hg
annotate mercurial/pure/base85.py @ 20870:6500a2eebee8
merge with stable
author | Matt Mackall <mpm@selenic.com> |
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date | Tue, 01 Apr 2014 15:11:19 -0500 |
parents | 20a9d823f242 |
children | 9007f697e8ef |
rev | line source |
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7701 | 1 # base85.py: pure python base85 codec |
2 # | |
3 # Copyright (C) 2009 Brendan Cully <brendan@kublai.com> | |
4 # | |
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5 # This software may be used and distributed according to the terms of the |
10263 | 6 # GNU General Public License version 2 or any later version. |
7701 | 7 |
8 import struct | |
9 | |
10 _b85chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" \ | |
11 "abcdefghijklmnopqrstuvwxyz!#$%&()*+-;<=>?@^_`{|}~" | |
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12 _b85chars2 = [(a + b) for a in _b85chars for b in _b85chars] |
7701 | 13 _b85dec = {} |
14 | |
15 def _mkb85dec(): | |
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16 for i, c in enumerate(_b85chars): |
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17 _b85dec[c] = i |
7701 | 18 |
19 def b85encode(text, pad=False): | |
20 """encode text in base85 format""" | |
21 l = len(text) | |
22 r = l % 4 | |
23 if r: | |
24 text += '\0' * (4 - r) | |
25 longs = len(text) >> 2 | |
26 words = struct.unpack('>%dL' % (longs), text) | |
27 | |
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28 out = ''.join(_b85chars[(word // 52200625) % 85] + |
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29 _b85chars2[(word // 7225) % 7225] + |
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30 _b85chars2[word % 7225] |
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31 for word in words) |
7701 | 32 |
33 if pad: | |
34 return out | |
35 | |
36 # Trim padding | |
37 olen = l % 4 | |
38 if olen: | |
39 olen += 1 | |
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40 olen += l // 4 * 5 |
7701 | 41 return out[:olen] |
42 | |
43 def b85decode(text): | |
44 """decode base85-encoded text""" | |
45 if not _b85dec: | |
46 _mkb85dec() | |
47 | |
48 l = len(text) | |
49 out = [] | |
50 for i in range(0, len(text), 5): | |
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51 chunk = text[i:i + 5] |
7701 | 52 acc = 0 |
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53 for j, c in enumerate(chunk): |
7701 | 54 try: |
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55 acc = acc * 85 + _b85dec[c] |
7701 | 56 except KeyError: |
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57 raise ValueError('bad base85 character at position %d' |
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58 % (i + j)) |
7701 | 59 if acc > 4294967295: |
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60 raise ValueError('Base85 overflow in hunk starting at byte %d' % i) |
7701 | 61 out.append(acc) |
62 | |
63 # Pad final chunk if necessary | |
64 cl = l % 5 | |
65 if cl: | |
66 acc *= 85 ** (5 - cl) | |
67 if cl > 1: | |
68 acc += 0xffffff >> (cl - 2) * 8 | |
69 out[-1] = acc | |
70 | |
71 out = struct.pack('>%dL' % (len(out)), *out) | |
72 if cl: | |
73 out = out[:-(5 - cl)] | |
74 | |
75 return out |