Mercurial > hg
annotate mercurial/bdiff.c @ 30439:71b368e3b590
bundle2: equate 'UN' with no compression
An upcoming patch will change the "alg" argument passed to this
function from None to "UN" when no compression is wanted.
The existing implementation of bundle2 does not set a "Compression"
parameter if no compression is used. In theory, setting
"Compression=UN" should work. But I haven't audited the code to see if
all client versions supporting bundle2 will accept this.
Rather than take the risk, avoid the BC breakage and treat "UN"
the same as None.
author | Gregory Szorc <gregory.szorc@gmail.com> |
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date | Thu, 10 Nov 2016 23:29:01 -0800 |
parents | 96f2f50d923f |
children | d195fa651b51 |
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1 /* |
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2 bdiff.c - efficient binary diff extension for Mercurial |
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3 |
2859 | 4 Copyright 2005, 2006 Matt Mackall <mpm@selenic.com> |
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5 |
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6 This software may be used and distributed according to the terms of |
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7 the GNU General Public License, incorporated herein by reference. |
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8 |
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9 Based roughly on Python difflib |
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10 */ |
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11 |
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12 #include <stdlib.h> |
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13 #include <string.h> |
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14 #include <limits.h> |
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15 |
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16 #include "compat.h" |
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17 #include "bitmanipulation.h" |
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18 #include "bdiff.h" |
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19 |
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20 /* Hash implementation from diffutils */ |
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21 #define ROL(v, n) ((v) << (n) | (v) >> (sizeof(v) * CHAR_BIT - (n))) |
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22 #define HASH(h, c) ((c) + ROL(h ,7)) |
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23 |
474 | 24 struct pos { |
25 int pos, len; | |
26 }; | |
27 | |
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28 int bdiff_splitlines(const char *a, ssize_t len, struct bdiff_line **lr) |
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29 { |
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30 unsigned hash; |
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31 int i; |
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32 const char *p, *b = a; |
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33 const char * const plast = a + len - 1; |
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34 struct bdiff_line *l; |
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35 |
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36 /* count the lines */ |
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37 i = 1; /* extra line for sentinel */ |
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38 for (p = a; p < plast; p++) |
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39 if (*p == '\n') |
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40 i++; |
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41 if (p == plast) |
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42 i++; |
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43 |
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44 *lr = l = (struct bdiff_line *)malloc(sizeof(struct bdiff_line) * i); |
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45 if (!l) |
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46 return -1; |
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47 |
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48 /* build the line array and calculate hashes */ |
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49 hash = 0; |
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50 for (p = a; p < a + len; p++) { |
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51 hash = HASH(hash, *p); |
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53 if (*p == '\n' || p == plast) { |
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54 l->hash = hash; |
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55 hash = 0; |
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56 l->len = p - b + 1; |
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57 l->l = b; |
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58 l->n = INT_MAX; |
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59 l++; |
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60 b = p + 1; |
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61 } |
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62 } |
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63 |
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64 /* set up a sentinel */ |
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65 l->hash = 0; |
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66 l->len = 0; |
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67 l->l = a + len; |
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68 return i - 1; |
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69 } |
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70 |
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71 static inline int cmp(struct bdiff_line *a, struct bdiff_line *b) |
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72 { |
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73 return a->hash != b->hash || a->len != b->len || memcmp(a->l, b->l, a->len); |
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74 } |
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75 |
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76 static int equatelines(struct bdiff_line *a, int an, struct bdiff_line *b, |
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77 int bn) |
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78 { |
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79 int i, j, buckets = 1, t, scale; |
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80 struct pos *h = NULL; |
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81 |
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82 /* build a hash table of the next highest power of 2 */ |
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83 while (buckets < bn + 1) |
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84 buckets *= 2; |
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85 |
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86 /* try to allocate a large hash table to avoid collisions */ |
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87 for (scale = 4; scale; scale /= 2) { |
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88 h = (struct pos *)malloc(scale * buckets * sizeof(struct pos)); |
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89 if (h) |
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90 break; |
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91 } |
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474 | 93 if (!h) |
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94 return 0; |
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95 |
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96 buckets = buckets * scale - 1; |
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97 |
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98 /* clear the hash table */ |
474 | 99 for (i = 0; i <= buckets; i++) { |
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100 h[i].pos = -1; |
474 | 101 h[i].len = 0; |
102 } | |
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103 |
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104 /* add lines to the hash table chains */ |
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105 for (i = 0; i < bn; i++) { |
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106 /* find the equivalence class */ |
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107 for (j = b[i].hash & buckets; h[j].pos != -1; |
474 | 108 j = (j + 1) & buckets) |
109 if (!cmp(b + i, b + h[j].pos)) | |
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110 break; |
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111 |
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112 /* add to the head of the equivalence class */ |
474 | 113 b[i].n = h[j].pos; |
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114 b[i].e = j; |
474 | 115 h[j].pos = i; |
116 h[j].len++; /* keep track of popularity */ | |
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117 } |
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118 |
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119 /* compute popularity threshold */ |
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120 t = (bn >= 31000) ? bn / 1000 : 1000000 / (bn + 1); |
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121 |
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122 /* match items in a to their equivalence class in b */ |
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123 for (i = 0; i < an; i++) { |
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124 /* find the equivalence class */ |
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125 for (j = a[i].hash & buckets; h[j].pos != -1; |
474 | 126 j = (j + 1) & buckets) |
127 if (!cmp(a + i, b + h[j].pos)) | |
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128 break; |
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129 |
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130 a[i].e = j; /* use equivalence class for quick compare */ |
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131 if (h[j].len <= t) |
474 | 132 a[i].n = h[j].pos; /* point to head of match list */ |
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133 else |
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134 a[i].n = -1; /* too popular */ |
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135 } |
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136 |
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137 /* discard hash tables */ |
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138 free(h); |
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139 return 1; |
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140 } |
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141 |
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142 static int longest_match(struct bdiff_line *a, struct bdiff_line *b, |
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143 struct pos *pos, |
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144 int a1, int a2, int b1, int b2, int *omi, int *omj) |
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145 { |
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146 int mi = a1, mj = b1, mk = 0, i, j, k, half, bhalf; |
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147 |
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148 /* window our search on large regions to better bound |
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149 worst-case performance. by choosing a window at the end, we |
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150 reduce skipping overhead on the b chains. */ |
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151 if (a2 - a1 > 30000) |
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152 a1 = a2 - 30000; |
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153 |
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154 half = (a1 + a2 - 1) / 2; |
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155 bhalf = (b1 + b2 - 1) / 2; |
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156 |
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157 for (i = a1; i < a2; i++) { |
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158 /* skip all lines in b after the current block */ |
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159 for (j = a[i].n; j >= b2; j = b[j].n) |
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160 ; |
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161 |
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162 /* loop through all lines match a[i] in b */ |
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163 for (; j >= b1; j = b[j].n) { |
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164 /* does this extend an earlier match? */ |
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165 for (k = 1; j - k >= b1 && i - k >= a1; k++) { |
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166 /* reached an earlier match? */ |
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167 if (pos[j - k].pos == i - k) { |
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168 k += pos[j - k].len; |
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169 break; |
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170 } |
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171 /* previous line mismatch? */ |
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172 if (a[i - k].e != b[j - k].e) |
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173 break; |
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174 } |
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175 |
474 | 176 pos[j].pos = i; |
177 pos[j].len = k; | |
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178 |
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179 /* best match so far? we prefer matches closer |
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180 to the middle to balance recursion */ |
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181 if (k > mk) { |
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182 /* a longer match */ |
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183 mi = i; |
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184 mj = j; |
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185 mk = k; |
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186 } else if (k == mk) { |
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187 if (i > mi && i <= half && j > b1) { |
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188 /* same match but closer to half */ |
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189 mi = i; |
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190 mj = j; |
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191 } else if (i == mi && (mj > bhalf || i == a1)) { |
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192 /* same i but best earlier j */ |
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193 mj = j; |
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194 } |
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195 } |
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196 } |
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197 } |
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198 |
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199 if (mk) { |
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200 mi = mi - mk + 1; |
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201 mj = mj - mk + 1; |
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202 } |
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203 |
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204 /* expand match to include subsequent popular lines */ |
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205 while (mi + mk < a2 && mj + mk < b2 && |
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206 a[mi + mk].e == b[mj + mk].e) |
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207 mk++; |
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208 |
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209 *omi = mi; |
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210 *omj = mj; |
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211 |
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212 return mk; |
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213 } |
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214 |
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215 static struct bdiff_hunk *recurse(struct bdiff_line *a, struct bdiff_line *b, |
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216 struct pos *pos, |
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217 int a1, int a2, int b1, int b2, struct bdiff_hunk *l) |
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218 { |
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219 int i, j, k; |
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220 |
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221 while (1) { |
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222 /* find the longest match in this chunk */ |
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223 k = longest_match(a, b, pos, a1, a2, b1, b2, &i, &j); |
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224 if (!k) |
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225 return l; |
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226 |
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227 /* and recurse on the remaining chunks on either side */ |
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228 l = recurse(a, b, pos, a1, i, b1, j, l); |
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229 if (!l) |
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230 return NULL; |
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231 |
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232 l->next = (struct bdiff_hunk *)malloc(sizeof(struct bdiff_hunk)); |
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233 if (!l->next) |
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234 return NULL; |
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235 |
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236 l = l->next; |
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237 l->a1 = i; |
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238 l->a2 = i + k; |
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239 l->b1 = j; |
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240 l->b2 = j + k; |
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241 l->next = NULL; |
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242 |
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243 /* tail-recursion didn't happen, so do equivalent iteration */ |
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244 a1 = i + k; |
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245 b1 = j + k; |
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246 } |
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247 } |
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248 |
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249 int bdiff_diff(struct bdiff_line *a, int an, struct bdiff_line *b, |
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250 int bn, struct bdiff_hunk *base) |
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251 { |
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252 struct bdiff_hunk *curr; |
474 | 253 struct pos *pos; |
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254 int t, count = 0; |
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255 |
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256 /* allocate and fill arrays */ |
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257 t = equatelines(a, an, b, bn); |
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259 |
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260 if (pos && t) { |
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261 /* generate the matching block list */ |
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262 |
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263 curr = recurse(a, b, pos, 0, an, 0, bn, base); |
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264 if (!curr) |
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265 return -1; |
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266 |
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267 /* sentinel end hunk */ |
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268 curr->next = (struct bdiff_hunk *)malloc(sizeof(struct bdiff_hunk)); |
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269 if (!curr->next) |
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270 return -1; |
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271 curr = curr->next; |
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272 curr->a1 = curr->a2 = an; |
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273 curr->b1 = curr->b2 = bn; |
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274 curr->next = NULL; |
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275 } |
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276 |
474 | 277 free(pos); |
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278 |
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279 /* normalize the hunk list, try to push each hunk towards the end */ |
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280 for (curr = base->next; curr; curr = curr->next) { |
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281 struct bdiff_hunk *next = curr->next; |
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282 |
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283 if (!next) |
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284 break; |
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285 |
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286 if (curr->a2 == next->a1 || curr->b2 == next->b1) |
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287 while (curr->a2 < an && curr->b2 < bn |
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288 && next->a1 < next->a2 |
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289 && next->b1 < next->b2 |
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290 && !cmp(a + curr->a2, b + curr->b2)) { |
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291 curr->a2++; |
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292 next->a1++; |
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293 curr->b2++; |
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294 next->b1++; |
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295 } |
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296 } |
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297 |
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298 for (curr = base->next; curr; curr = curr->next) |
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299 count++; |
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300 return count; |
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301 } |
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302 |
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303 void bdiff_freehunks(struct bdiff_hunk *l) |
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304 { |
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305 struct bdiff_hunk *n; |
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306 for (; l; l = n) { |
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307 n = l->next; |
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308 free(l); |
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309 } |
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310 } |
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311 |
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312 |