Mercurial > hg
annotate mercurial/bdiff.c @ 33352:967ac37f3d45
cleanupnode: do not use generator for node mapping
The 'successors' part of the mappings used of be a tuple. This avoid issue from
code consuming the generator "by mistake". For example, an extension inspecting the
mapping content used to be able to iterate over the successors mapping without
consequence.
Since the mapping are small we do not expect any performance impact we use tuple
again for this.
author | Octobus <contact@octobus.net> |
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date | Sun, 09 Jul 2017 15:11:19 +0200 |
parents | d195fa651b51 |
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1 /* |
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2 bdiff.c - efficient binary diff extension for Mercurial |
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3 |
2859 | 4 Copyright 2005, 2006 Matt Mackall <mpm@selenic.com> |
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5 |
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6 This software may be used and distributed according to the terms of |
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7 the GNU General Public License, incorporated herein by reference. |
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8 |
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9 Based roughly on Python difflib |
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10 */ |
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11 |
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12 #include <stdlib.h> |
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13 #include <string.h> |
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14 #include <limits.h> |
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15 |
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16 #include "compat.h" |
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17 #include "bitmanipulation.h" |
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18 #include "bdiff.h" |
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19 |
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20 /* Hash implementation from diffutils */ |
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21 #define ROL(v, n) ((v) << (n) | (v) >> (sizeof(v) * CHAR_BIT - (n))) |
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22 #define HASH(h, c) ((c) + ROL(h ,7)) |
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23 |
474 | 24 struct pos { |
25 int pos, len; | |
26 }; | |
27 | |
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28 int bdiff_splitlines(const char *a, ssize_t len, struct bdiff_line **lr) |
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29 { |
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30 unsigned hash; |
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31 int i; |
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32 const char *p, *b = a; |
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33 const char * const plast = a + len - 1; |
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34 struct bdiff_line *l; |
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35 |
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36 /* count the lines */ |
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37 i = 1; /* extra line for sentinel */ |
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38 for (p = a; p < plast; p++) |
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39 if (*p == '\n') |
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40 i++; |
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41 if (p == plast) |
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42 i++; |
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43 |
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44 *lr = l = (struct bdiff_line *)malloc(sizeof(struct bdiff_line) * i); |
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45 if (!l) |
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46 return -1; |
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47 |
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48 /* build the line array and calculate hashes */ |
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49 hash = 0; |
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50 for (p = a; p < plast; p++) { |
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51 hash = HASH(hash, *p); |
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53 if (*p == '\n') { |
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54 l->hash = hash; |
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55 hash = 0; |
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56 l->len = p - b + 1; |
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57 l->l = b; |
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58 l->n = INT_MAX; |
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59 l++; |
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60 b = p + 1; |
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61 } |
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62 } |
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63 |
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64 if (p == plast) { |
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65 hash = HASH(hash, *p); |
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66 l->hash = hash; |
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67 l->len = p - b + 1; |
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68 l->l = b; |
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69 l->n = INT_MAX; |
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70 l++; |
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71 } |
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72 |
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73 /* set up a sentinel */ |
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74 l->hash = 0; |
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75 l->len = 0; |
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76 l->l = a + len; |
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77 return i - 1; |
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78 } |
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79 |
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80 static inline int cmp(struct bdiff_line *a, struct bdiff_line *b) |
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81 { |
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82 return a->hash != b->hash || a->len != b->len || memcmp(a->l, b->l, a->len); |
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83 } |
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84 |
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85 static int equatelines(struct bdiff_line *a, int an, struct bdiff_line *b, |
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86 int bn) |
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87 { |
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88 int i, j, buckets = 1, t, scale; |
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89 struct pos *h = NULL; |
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90 |
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91 /* build a hash table of the next highest power of 2 */ |
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92 while (buckets < bn + 1) |
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93 buckets *= 2; |
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94 |
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95 /* try to allocate a large hash table to avoid collisions */ |
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96 for (scale = 4; scale; scale /= 2) { |
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97 h = (struct pos *)malloc(scale * buckets * sizeof(struct pos)); |
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98 if (h) |
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99 break; |
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100 } |
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474 | 102 if (!h) |
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103 return 0; |
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104 |
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105 buckets = buckets * scale - 1; |
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106 |
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107 /* clear the hash table */ |
474 | 108 for (i = 0; i <= buckets; i++) { |
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109 h[i].pos = -1; |
474 | 110 h[i].len = 0; |
111 } | |
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112 |
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113 /* add lines to the hash table chains */ |
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114 for (i = 0; i < bn; i++) { |
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115 /* find the equivalence class */ |
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116 for (j = b[i].hash & buckets; h[j].pos != -1; |
474 | 117 j = (j + 1) & buckets) |
118 if (!cmp(b + i, b + h[j].pos)) | |
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119 break; |
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120 |
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121 /* add to the head of the equivalence class */ |
474 | 122 b[i].n = h[j].pos; |
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123 b[i].e = j; |
474 | 124 h[j].pos = i; |
125 h[j].len++; /* keep track of popularity */ | |
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126 } |
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127 |
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128 /* compute popularity threshold */ |
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129 t = (bn >= 31000) ? bn / 1000 : 1000000 / (bn + 1); |
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130 |
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131 /* match items in a to their equivalence class in b */ |
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132 for (i = 0; i < an; i++) { |
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133 /* find the equivalence class */ |
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134 for (j = a[i].hash & buckets; h[j].pos != -1; |
474 | 135 j = (j + 1) & buckets) |
136 if (!cmp(a + i, b + h[j].pos)) | |
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137 break; |
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138 |
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139 a[i].e = j; /* use equivalence class for quick compare */ |
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140 if (h[j].len <= t) |
474 | 141 a[i].n = h[j].pos; /* point to head of match list */ |
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142 else |
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143 a[i].n = -1; /* too popular */ |
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144 } |
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145 |
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146 /* discard hash tables */ |
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147 free(h); |
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148 return 1; |
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149 } |
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150 |
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151 static int longest_match(struct bdiff_line *a, struct bdiff_line *b, |
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152 struct pos *pos, |
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153 int a1, int a2, int b1, int b2, int *omi, int *omj) |
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154 { |
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155 int mi = a1, mj = b1, mk = 0, i, j, k, half, bhalf; |
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156 |
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157 /* window our search on large regions to better bound |
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158 worst-case performance. by choosing a window at the end, we |
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159 reduce skipping overhead on the b chains. */ |
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160 if (a2 - a1 > 30000) |
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161 a1 = a2 - 30000; |
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162 |
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163 half = (a1 + a2 - 1) / 2; |
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164 bhalf = (b1 + b2 - 1) / 2; |
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165 |
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166 for (i = a1; i < a2; i++) { |
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167 /* skip all lines in b after the current block */ |
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168 for (j = a[i].n; j >= b2; j = b[j].n) |
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169 ; |
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170 |
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171 /* loop through all lines match a[i] in b */ |
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172 for (; j >= b1; j = b[j].n) { |
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173 /* does this extend an earlier match? */ |
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174 for (k = 1; j - k >= b1 && i - k >= a1; k++) { |
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175 /* reached an earlier match? */ |
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176 if (pos[j - k].pos == i - k) { |
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177 k += pos[j - k].len; |
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178 break; |
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179 } |
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180 /* previous line mismatch? */ |
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181 if (a[i - k].e != b[j - k].e) |
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182 break; |
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183 } |
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184 |
474 | 185 pos[j].pos = i; |
186 pos[j].len = k; | |
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187 |
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188 /* best match so far? we prefer matches closer |
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189 to the middle to balance recursion */ |
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190 if (k > mk) { |
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191 /* a longer match */ |
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192 mi = i; |
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193 mj = j; |
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194 mk = k; |
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195 } else if (k == mk) { |
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196 if (i > mi && i <= half && j > b1) { |
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197 /* same match but closer to half */ |
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198 mi = i; |
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199 mj = j; |
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200 } else if (i == mi && (mj > bhalf || i == a1)) { |
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201 /* same i but best earlier j */ |
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202 mj = j; |
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203 } |
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204 } |
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205 } |
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206 } |
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207 |
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208 if (mk) { |
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209 mi = mi - mk + 1; |
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210 mj = mj - mk + 1; |
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211 } |
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212 |
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213 /* expand match to include subsequent popular lines */ |
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214 while (mi + mk < a2 && mj + mk < b2 && |
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215 a[mi + mk].e == b[mj + mk].e) |
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216 mk++; |
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217 |
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218 *omi = mi; |
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219 *omj = mj; |
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220 |
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221 return mk; |
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222 } |
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223 |
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224 static struct bdiff_hunk *recurse(struct bdiff_line *a, struct bdiff_line *b, |
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225 struct pos *pos, |
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226 int a1, int a2, int b1, int b2, struct bdiff_hunk *l) |
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227 { |
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228 int i, j, k; |
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229 |
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230 while (1) { |
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231 /* find the longest match in this chunk */ |
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232 k = longest_match(a, b, pos, a1, a2, b1, b2, &i, &j); |
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233 if (!k) |
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234 return l; |
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235 |
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236 /* and recurse on the remaining chunks on either side */ |
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237 l = recurse(a, b, pos, a1, i, b1, j, l); |
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238 if (!l) |
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239 return NULL; |
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240 |
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241 l->next = (struct bdiff_hunk *)malloc(sizeof(struct bdiff_hunk)); |
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242 if (!l->next) |
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243 return NULL; |
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244 |
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245 l = l->next; |
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246 l->a1 = i; |
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247 l->a2 = i + k; |
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248 l->b1 = j; |
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249 l->b2 = j + k; |
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250 l->next = NULL; |
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251 |
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252 /* tail-recursion didn't happen, so do equivalent iteration */ |
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253 a1 = i + k; |
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254 b1 = j + k; |
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255 } |
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256 } |
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257 |
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258 int bdiff_diff(struct bdiff_line *a, int an, struct bdiff_line *b, |
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259 int bn, struct bdiff_hunk *base) |
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260 { |
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261 struct bdiff_hunk *curr; |
474 | 262 struct pos *pos; |
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263 int t, count = 0; |
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264 |
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265 /* allocate and fill arrays */ |
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266 t = equatelines(a, an, b, bn); |
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268 |
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269 if (pos && t) { |
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270 /* generate the matching block list */ |
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271 |
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272 curr = recurse(a, b, pos, 0, an, 0, bn, base); |
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273 if (!curr) |
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274 return -1; |
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275 |
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276 /* sentinel end hunk */ |
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277 curr->next = (struct bdiff_hunk *)malloc(sizeof(struct bdiff_hunk)); |
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278 if (!curr->next) |
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279 return -1; |
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280 curr = curr->next; |
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281 curr->a1 = curr->a2 = an; |
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282 curr->b1 = curr->b2 = bn; |
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283 curr->next = NULL; |
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284 } |
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285 |
474 | 286 free(pos); |
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287 |
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288 /* normalize the hunk list, try to push each hunk towards the end */ |
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289 for (curr = base->next; curr; curr = curr->next) { |
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290 struct bdiff_hunk *next = curr->next; |
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291 |
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292 if (!next) |
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293 break; |
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294 |
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295 if (curr->a2 == next->a1 || curr->b2 == next->b1) |
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296 while (curr->a2 < an && curr->b2 < bn |
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297 && next->a1 < next->a2 |
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298 && next->b1 < next->b2 |
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299 && !cmp(a + curr->a2, b + curr->b2)) { |
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300 curr->a2++; |
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301 next->a1++; |
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302 curr->b2++; |
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303 next->b1++; |
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304 } |
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305 } |
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306 |
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307 for (curr = base->next; curr; curr = curr->next) |
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308 count++; |
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309 return count; |
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310 } |
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311 |
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312 void bdiff_freehunks(struct bdiff_hunk *l) |
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313 { |
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314 struct bdiff_hunk *n; |
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315 for (; l; l = n) { |
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316 n = l->next; |
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317 free(l); |
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318 } |
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319 } |
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320 |
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321 |