Mercurial > hg
annotate mercurial/bdiff.c @ 45326:99614011892b
commitctx: directly gather p1 and p2 copies in `files`
The only thing we do with the p1copies and p2copies is to pass them around, we
we can gather them later and directly stored them in the `ChangingFiles` object.
author | Pierre-Yves David <pierre-yves.david@octobus.net> |
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date | Sat, 25 Jul 2020 16:07:38 +0200 |
parents | 763b45bc4483 |
children | d4ba4d51f85f |
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1 /* |
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2 bdiff.c - efficient binary diff extension for Mercurial |
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3 |
2859 | 4 Copyright 2005, 2006 Matt Mackall <mpm@selenic.com> |
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5 |
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6 This software may be used and distributed according to the terms of |
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7 the GNU General Public License, incorporated herein by reference. |
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8 |
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9 Based roughly on Python difflib |
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10 */ |
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11 |
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12 #include <limits.h> |
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13 #include <stdlib.h> |
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14 #include <string.h> |
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15 |
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16 #include "bdiff.h" |
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17 #include "bitmanipulation.h" |
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18 #include "compat.h" |
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19 |
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20 /* Hash implementation from diffutils */ |
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21 #define ROL(v, n) ((v) << (n) | (v) >> (sizeof(v) * CHAR_BIT - (n))) |
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22 #define HASH(h, c) ((c) + ROL(h, 7)) |
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23 |
474 | 24 struct pos { |
25 int pos, len; | |
26 }; | |
27 | |
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28 int bdiff_splitlines(const char *a, ssize_t len, struct bdiff_line **lr) |
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29 { |
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30 unsigned hash; |
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31 int i; |
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32 const char *p, *b = a; |
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33 const char *const plast = a + len - 1; |
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34 struct bdiff_line *l; |
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35 |
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36 /* count the lines */ |
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37 i = 1; /* extra line for sentinel */ |
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38 for (p = a; p < plast; p++) { |
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39 if (*p == '\n') { |
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40 i++; |
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41 } |
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42 } |
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43 if (p == plast) { |
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44 i++; |
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45 } |
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46 |
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47 *lr = l = (struct bdiff_line *)calloc(i, sizeof(struct bdiff_line)); |
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48 if (!l) { |
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49 return -1; |
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50 } |
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51 |
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52 /* build the line array and calculate hashes */ |
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53 hash = 0; |
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54 for (p = a; p < plast; p++) { |
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55 hash = HASH(hash, *p); |
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57 if (*p == '\n') { |
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58 l->hash = hash; |
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59 hash = 0; |
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60 l->len = p - b + 1; |
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61 l->l = b; |
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62 l->n = INT_MAX; |
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63 l++; |
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64 b = p + 1; |
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65 } |
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66 } |
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67 |
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68 if (p == plast) { |
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69 hash = HASH(hash, *p); |
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70 l->hash = hash; |
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71 l->len = p - b + 1; |
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72 l->l = b; |
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73 l->n = INT_MAX; |
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74 l++; |
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75 } |
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76 |
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77 /* set up a sentinel */ |
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78 l->hash = 0; |
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79 l->len = 0; |
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80 l->l = a + len; |
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81 return i - 1; |
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82 } |
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83 |
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84 static inline int cmp(struct bdiff_line *a, struct bdiff_line *b) |
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85 { |
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86 return a->hash != b->hash || a->len != b->len || |
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87 memcmp(a->l, b->l, a->len); |
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88 } |
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89 |
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90 static int equatelines(struct bdiff_line *a, int an, struct bdiff_line *b, |
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91 int bn) |
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92 { |
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93 int i, j, buckets = 1, t, scale; |
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94 struct pos *h = NULL; |
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95 |
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96 /* build a hash table of the next highest power of 2 */ |
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97 while (buckets < bn + 1) { |
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98 buckets *= 2; |
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99 } |
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100 |
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101 /* try to allocate a large hash table to avoid collisions */ |
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102 for (scale = 4; scale; scale /= 2) { |
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103 h = (struct pos *)calloc(buckets, scale * sizeof(struct pos)); |
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104 if (h) { |
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105 break; |
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106 } |
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107 } |
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108 |
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109 if (!h) { |
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110 return 0; |
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111 } |
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112 |
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113 buckets = buckets * scale - 1; |
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114 |
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115 /* clear the hash table */ |
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117 h[i].pos = -1; |
474 | 118 h[i].len = 0; |
119 } | |
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120 |
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121 /* add lines to the hash table chains */ |
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122 for (i = 0; i < bn; i++) { |
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123 /* find the equivalence class */ |
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124 for (j = b[i].hash & buckets; h[j].pos != -1; |
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125 j = (j + 1) & buckets) { |
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126 if (!cmp(b + i, b + h[j].pos)) { |
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127 break; |
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128 } |
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129 } |
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130 |
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131 /* add to the head of the equivalence class */ |
474 | 132 b[i].n = h[j].pos; |
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133 b[i].e = j; |
474 | 134 h[j].pos = i; |
135 h[j].len++; /* keep track of popularity */ | |
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136 } |
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137 |
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138 /* compute popularity threshold */ |
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139 t = (bn >= 31000) ? bn / 1000 : 1000000 / (bn + 1); |
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140 |
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141 /* match items in a to their equivalence class in b */ |
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142 for (i = 0; i < an; i++) { |
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143 /* find the equivalence class */ |
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144 for (j = a[i].hash & buckets; h[j].pos != -1; |
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145 j = (j + 1) & buckets) { |
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146 if (!cmp(a + i, b + h[j].pos)) { |
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147 break; |
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148 } |
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149 } |
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150 |
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151 a[i].e = j; /* use equivalence class for quick compare */ |
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152 if (h[j].len <= t) { |
474 | 153 a[i].n = h[j].pos; /* point to head of match list */ |
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154 } else { |
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155 a[i].n = -1; /* too popular */ |
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156 } |
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157 } |
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158 |
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159 /* discard hash tables */ |
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160 free(h); |
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161 return 1; |
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162 } |
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163 |
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164 static int longest_match(struct bdiff_line *a, struct bdiff_line *b, |
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165 struct pos *pos, int a1, int a2, int b1, int b2, |
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166 int *omi, int *omj) |
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167 { |
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168 int mi = a1, mj = b1, mk = 0, i, j, k, half, bhalf; |
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169 |
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170 /* window our search on large regions to better bound |
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171 worst-case performance. by choosing a window at the end, we |
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172 reduce skipping overhead on the b chains. */ |
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173 if (a2 - a1 > 30000) { |
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174 a1 = a2 - 30000; |
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175 } |
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176 |
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177 half = (a1 + a2 - 1) / 2; |
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178 bhalf = (b1 + b2 - 1) / 2; |
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179 |
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180 for (i = a1; i < a2; i++) { |
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181 /* skip all lines in b after the current block */ |
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182 for (j = a[i].n; j >= b2; j = b[j].n) { |
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183 ; |
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184 } |
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185 |
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186 /* loop through all lines match a[i] in b */ |
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187 for (; j >= b1; j = b[j].n) { |
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188 /* does this extend an earlier match? */ |
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189 for (k = 1; j - k >= b1 && i - k >= a1; k++) { |
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190 /* reached an earlier match? */ |
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191 if (pos[j - k].pos == i - k) { |
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192 k += pos[j - k].len; |
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193 break; |
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194 } |
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195 /* previous line mismatch? */ |
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196 if (a[i - k].e != b[j - k].e) { |
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197 break; |
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198 } |
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199 } |
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200 |
474 | 201 pos[j].pos = i; |
202 pos[j].len = k; | |
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203 |
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204 /* best match so far? we prefer matches closer |
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205 to the middle to balance recursion */ |
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206 if (k > mk) { |
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207 /* a longer match */ |
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208 mi = i; |
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209 mj = j; |
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210 mk = k; |
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211 } else if (k == mk) { |
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212 if (i > mi && i <= half && j > b1) { |
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213 /* same match but closer to half */ |
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214 mi = i; |
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215 mj = j; |
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216 } else if (i == mi && (mj > bhalf || i == a1)) { |
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217 /* same i but best earlier j */ |
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218 mj = j; |
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219 } |
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220 } |
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221 } |
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222 } |
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223 |
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224 if (mk) { |
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225 mi = mi - mk + 1; |
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226 mj = mj - mk + 1; |
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227 } |
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228 |
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229 /* expand match to include subsequent popular lines */ |
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230 while (mi + mk < a2 && mj + mk < b2 && a[mi + mk].e == b[mj + mk].e) { |
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231 mk++; |
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232 } |
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233 |
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234 *omi = mi; |
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235 *omj = mj; |
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236 |
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237 return mk; |
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238 } |
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239 |
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240 static struct bdiff_hunk *recurse(struct bdiff_line *a, struct bdiff_line *b, |
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241 struct pos *pos, int a1, int a2, int b1, |
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242 int b2, struct bdiff_hunk *l) |
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243 { |
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244 int i, j, k; |
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245 |
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246 while (1) { |
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247 /* find the longest match in this chunk */ |
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248 k = longest_match(a, b, pos, a1, a2, b1, b2, &i, &j); |
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249 if (!k) { |
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250 return l; |
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251 } |
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252 |
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253 /* and recurse on the remaining chunks on either side */ |
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254 l = recurse(a, b, pos, a1, i, b1, j, l); |
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255 if (!l) { |
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256 return NULL; |
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257 } |
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258 |
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259 l->next = |
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260 (struct bdiff_hunk *)malloc(sizeof(struct bdiff_hunk)); |
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261 if (!l->next) { |
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262 return NULL; |
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263 } |
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264 |
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265 l = l->next; |
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266 l->a1 = i; |
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267 l->a2 = i + k; |
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268 l->b1 = j; |
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269 l->b2 = j + k; |
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270 l->next = NULL; |
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271 |
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272 /* tail-recursion didn't happen, so do equivalent iteration */ |
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273 a1 = i + k; |
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274 b1 = j + k; |
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275 } |
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276 } |
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277 |
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278 int bdiff_diff(struct bdiff_line *a, int an, struct bdiff_line *b, int bn, |
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279 struct bdiff_hunk *base) |
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280 { |
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281 struct bdiff_hunk *curr; |
474 | 282 struct pos *pos; |
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283 int t, count = 0; |
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284 |
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285 /* allocate and fill arrays */ |
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286 t = equatelines(a, an, b, bn); |
5571 | 287 pos = (struct pos *)calloc(bn ? bn : 1, sizeof(struct pos)); |
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288 |
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289 if (pos && t) { |
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290 /* generate the matching block list */ |
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291 |
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292 curr = recurse(a, b, pos, 0, an, 0, bn, base); |
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293 if (!curr) { |
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294 return -1; |
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295 } |
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296 |
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297 /* sentinel end hunk */ |
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298 curr->next = |
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299 (struct bdiff_hunk *)malloc(sizeof(struct bdiff_hunk)); |
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300 if (!curr->next) { |
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301 return -1; |
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302 } |
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303 curr = curr->next; |
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304 curr->a1 = curr->a2 = an; |
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305 curr->b1 = curr->b2 = bn; |
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306 curr->next = NULL; |
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307 } |
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308 |
474 | 309 free(pos); |
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310 |
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311 /* normalize the hunk list, try to push each hunk towards the end */ |
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312 for (curr = base->next; curr; curr = curr->next) { |
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313 struct bdiff_hunk *next = curr->next; |
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314 |
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315 if (!next) { |
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316 break; |
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317 } |
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318 |
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319 if (curr->a2 == next->a1 || curr->b2 == next->b1) { |
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320 while (curr->a2 < an && curr->b2 < bn && |
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321 next->a1 < next->a2 && next->b1 < next->b2 && |
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322 !cmp(a + curr->a2, b + curr->b2)) { |
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323 curr->a2++; |
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324 next->a1++; |
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325 curr->b2++; |
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326 next->b1++; |
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327 } |
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328 } |
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329 } |
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330 |
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331 for (curr = base->next; curr; curr = curr->next) { |
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332 count++; |
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333 } |
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334 return count; |
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335 } |
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336 |
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337 /* deallocate list of hunks; l may be NULL */ |
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338 void bdiff_freehunks(struct bdiff_hunk *l) |
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339 { |
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340 struct bdiff_hunk *n; |
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341 for (; l; l = n) { |
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342 n = l->next; |
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343 free(l); |
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344 } |
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345 } |