annotate mercurial/ancestor.py @ 16705:c2d9ef43ff6c

check-code: ignore naked excepts with a "re-raise" comment This also promotes the naked except check from a warning to an error.
author Brodie Rao <brodie@sf.io>
date Sun, 13 May 2012 13:18:06 +0200
parents 1ffeeb91c55d
children 0b03454abae7
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1 # ancestor.py - generic DAG ancestor algorithm for mercurial
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2 #
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3 # Copyright 2006 Matt Mackall <mpm@selenic.com>
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4 #
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5 # This software may be used and distributed according to the terms of the
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6 # GNU General Public License version 2 or any later version.
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7
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8 import heapq
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9
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10 def ancestor(a, b, pfunc):
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11 """
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12 Returns the common ancestor of a and b that is furthest from a
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13 root (as measured by longest path) or None if no ancestor is
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14 found. If there are multiple common ancestors at the same
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15 distance, the first one found is returned.
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16
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17 pfunc must return a list of parent vertices for a given vertex
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18 """
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19
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20 if a == b:
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21 return a
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22
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23 a, b = sorted([a, b])
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24
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25 # find depth from root of all ancestors
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26 # depth is stored as a negative for heapq
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27 parentcache = {}
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28 visit = [a, b]
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29 depth = {}
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30 while visit:
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31 vertex = visit[-1]
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32 pl = pfunc(vertex)
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33 parentcache[vertex] = pl
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34 if not pl:
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35 depth[vertex] = 0
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36 visit.pop()
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37 else:
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38 for p in pl:
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39 if p == a or p == b: # did we find a or b as a parent?
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40 return p # we're done
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41 if p not in depth:
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42 visit.append(p)
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43 if visit[-1] == vertex:
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44 # -(maximum distance of parents + 1)
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45 depth[vertex] = min([depth[p] for p in pl]) - 1
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46 visit.pop()
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47
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48 # traverse ancestors in order of decreasing distance from root
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49 def ancestors(vertex):
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50 h = [(depth[vertex], vertex)]
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51 seen = set()
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52 while h:
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53 d, n = heapq.heappop(h)
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54 if n not in seen:
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55 seen.add(n)
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56 yield (d, n)
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57 for p in parentcache[n]:
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58 heapq.heappush(h, (depth[p], p))
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59
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60 def generations(vertex):
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61 sg, s = None, set()
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62 for g, v in ancestors(vertex):
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63 if g != sg:
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64 if sg:
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65 yield sg, s
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66 sg, s = g, set((v,))
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67 else:
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68 s.add(v)
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69 yield sg, s
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70
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71 x = generations(a)
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72 y = generations(b)
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73 gx = x.next()
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74 gy = y.next()
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75
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76 # increment each ancestor list until it is closer to root than
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77 # the other, or they match
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78 try:
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79 while True:
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80 if gx[0] == gy[0]:
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81 for v in gx[1]:
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82 if v in gy[1]:
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83 return v
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84 gy = y.next()
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85 gx = x.next()
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86 elif gx[0] > gy[0]:
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87 gy = y.next()
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88 else:
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89 gx = x.next()
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90 except StopIteration:
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91 return None