annotate mercurial/tagmerge.py @ 23785:cb99bacb9b4e

branchcache: introduce revbranchcache for caching of revision branch names It is expensive to retrieve the branch name of a revision. Very expensive when creating a changectx and calling .branch() every time - slightly less when using changelog.branchinfo(). Now, to speed things up, provide a way to cache the results on disk in an efficient format. Each branchname is assigned a number, and for each revision we store the number of the corresponding branch name. The branch names are stored in a dedicated file which is strictly append only. Branch names are usually reused across several revisions, and the total list of branch names will thus be so small that it is feasible to read the whole set of names before using the cache. It will however do that it might be more efficient to use the changelog for retrieving the branch info for a single revision. The revision entries are stored in another file. This file is usually append only, but if the repository has been modified, the file will be truncated and the relevant parts rewritten on demand. The entries for each revision are 8 bytes each, and the whole revision file will thus be 1/8 of 00changelog.i. Each revision entry contains the first 4 bytes of the corresponding node hash. This is used as a check sum that always is verified before the entry is used. That check is relatively expensive but it makes sure history modification is detected and handled correctly. It will also detect and handle most revision file corruptions. This is just a cache. A new format can always be introduced if other requirements or ideas make that seem like a good idea. Rebuilding the cache is not really more expensive than it was to run for example 'hg log -b branchname' before this cache was introduced. This new method is still unused but promise to make some operations several times faster once it actually is used. Abandoning Python 2.4 would make it possible to implement this more efficiently by using struct classes and pack_into. The Python code could probably also be micro optimized or it could be implemented very efficiently in C where it would be easy to control the data access.
author Mads Kiilerich <madski@unity3d.com>
date Thu, 08 Jan 2015 00:01:03 +0100
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children fa91c49a9b9f
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1 # tagmerge.py - merge .hgtags files
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2 #
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3 # Copyright 2014 Angel Ezquerra <angel.ezquerra@gmail.com>
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4 #
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5 # This software may be used and distributed according to the terms of the
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6 # GNU General Public License version 2 or any later version.
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7
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8 # This module implements an automatic merge algorithm for mercurial's tag files
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9 #
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10 # The tagmerge algorithm implemented in this module is able to resolve most
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11 # merge conflicts that currently would trigger a .hgtags merge conflict. The
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12 # only case that it does not (and cannot) handle is that in which two tags point
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13 # to different revisions on each merge parent _and_ their corresponding tag
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14 # histories have the same rank (i.e. the same length). In all other cases the
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15 # merge algorithm will choose the revision belonging to the parent with the
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16 # highest ranked tag history. The merged tag history is the combination of both
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17 # tag histories (special care is taken to try to combine common tag histories
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18 # where possible).
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19 #
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20 # In addition to actually merging the tags from two parents, taking into
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21 # account the base, the algorithm also tries to minimize the difference
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22 # between the merged tag file and the first parent's tag file (i.e. it tries to
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23 # make the merged tag order as as similar as possible to the first parent's tag
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24 # file order).
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25 #
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26 # The algorithm works as follows:
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27 # 1. read the tags from p1, p2 and the base
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28 # - when reading the p1 tags, also get the line numbers associated to each
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29 # tag node (these will be used to sort the merged tags in a way that
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30 # minimizes the diff to p1). Ignore the file numbers when reading p2 and
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31 # the base
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32 # 2. recover the "lost tags" (i.e. those that are found in the base but not on
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33 # p1 or p2) and add them back to p1 and/or p2
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34 # - at this point the only tags that are on p1 but not on p2 are those new
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35 # tags that were introduced in p1. Same thing for the tags that are on p2
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36 # but not on p2
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37 # 3. take all tags that are only on p1 or only on p2 (but not on the base)
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38 # - Note that these are the tags that were introduced between base and p1
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39 # and between base and p2, possibly on separate clones
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40 # 4. for each tag found both on p1 and p2 perform the following merge algorithm:
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41 # - the tags conflict if their tag "histories" have the same "rank" (i.e.
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42 # length) AND the last (current) tag is NOT the same
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43 # - for non conflicting tags:
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44 # - choose which are the high and the low ranking nodes
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45 # - the high ranking list of nodes is the one that is longer.
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46 # In case of draw favor p1
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47 # - the merged node list is made of 3 parts:
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48 # - first the nodes that are common to the beginning of both
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49 # the low and the high ranking nodes
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50 # - second the non common low ranking nodes
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51 # - finally the non common high ranking nodes (with the last
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52 # one being the merged tag node)
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53 # - note that this is equivalent to putting the whole low ranking
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54 # node list first, followed by the non common high ranking nodes
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55 # - note that during the merge we keep the "node line numbers", which will
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56 # be used when writing the merged tags to the tag file
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57 # 5. write the merged tags taking into account to their positions in the first
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58 # parent (i.e. try to keep the relative ordering of the nodes that come
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59 # from p1). This minimizes the diff between the merged and the p1 tag files
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60 # This is done by using the following algorithm
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61 # - group the nodes for a given tag that must be written next to each other
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62 # - A: nodes that come from consecutive lines on p1
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63 # - B: nodes that come from p2 (i.e. whose associated line number is
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64 # None) and are next to one of the a nodes in A
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65 # - each group is associated with a line number coming from p1
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66 # - generate a "tag block" for each of the groups
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67 # - a tag block is a set of consecutive "node tag" lines belonging to
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68 # the same tag and which will be written next to each other on the
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69 # merged tags file
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70 # - sort the "tag blocks" according to their associated number line
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71 # - put blocks whose nodes come all from p2 first
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72 # - write the tag blocks in the sorted order
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73
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74 import tags as tagsmod
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75 import util
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76 from node import nullid, hex
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77 from i18n import _
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78 import operator
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79 hexnullid = hex(nullid)
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80
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81 def readtagsformerge(ui, repo, lines, fn='', keeplinenums=False):
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82 '''read the .hgtags file into a structure that is suitable for merging
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83
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84 Depending on the keeplinenums flag, clear the line numbers associated
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85 with each tag. This is done because only the line numbers of the first
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86 parent are useful for merging.
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87 '''
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88 filetags = tagsmod._readtaghist(ui, repo, lines, fn=fn, recode=None,
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89 calcnodelines=True)[1]
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90 for tagname, taginfo in filetags.items():
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91 if not keeplinenums:
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92 for el in taginfo:
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93 el[1] = None
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94 return filetags
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95
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96 def grouptagnodesbyline(tagnodes):
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97 '''
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98 Group nearby nodes (i.e. those that must be written next to each other)
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99
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100 The input is a list of [node, position] pairs, corresponding to a given tag
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101 The position is the line number where the node was found on the first parent
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102 .hgtags file, or None for those nodes that came from the base or the second
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103 parent .hgtags files.
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104
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105 This function groups those [node, position] pairs, returning a list of
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106 groups of nodes that must be written next to each other because their
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107 positions are consecutive or have no position preference (because their
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108 position is None).
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109
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110 The result is a list of [position, [consecutive node list]]
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111 '''
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112 firstlinenum = None
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113 for hexnode, linenum in tagnodes:
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114 firstlinenum = linenum
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115 if firstlinenum is not None:
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116 break
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117 if firstlinenum is None:
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118 return [[None, [el[0] for el in tagnodes]]]
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119 tagnodes[0][1] = firstlinenum
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120 groupednodes = [[firstlinenum, []]]
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121 prevlinenum = firstlinenum
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122 for hexnode, linenum in tagnodes:
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123 if linenum is not None and linenum - prevlinenum > 1:
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124 groupednodes.append([linenum, []])
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125 groupednodes[-1][1].append(hexnode)
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126 if linenum is not None:
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127 prevlinenum = linenum
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128 return groupednodes
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129
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130 def writemergedtags(repo, mergedtags):
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131 '''
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132 write the merged tags while trying to minimize the diff to the first parent
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133
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134 This function uses the ordering info stored on the merged tags dict to
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135 generate an .hgtags file which is correct (in the sense that its contents
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136 correspond to the result of the tag merge) while also being as close as
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137 possible to the first parent's .hgtags file.
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138 '''
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139 # group the node-tag pairs that must be written next to each other
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140 for tname, taglist in mergedtags.items():
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141 mergedtags[tname] = grouptagnodesbyline(taglist)
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142
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143 # convert the grouped merged tags dict into a format that resembles the
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144 # final .hgtags file (i.e. a list of blocks of 'node tag' pairs)
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145 def taglist2string(tlist, tname):
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146 return '\n'.join(['%s %s' % (hexnode, tname) for hexnode in tlist])
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147
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148 finaltags = []
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149 for tname, tags in mergedtags.items():
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150 for block in tags:
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151 block[1] = taglist2string(block[1], tname)
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152 finaltags += tags
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153
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154 # the tag groups are linked to a "position" that can be used to sort them
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155 # before writing them
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156 # the position is calculated to ensure that the diff of the merged .hgtags
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157 # file to the first parent's .hgtags file is as small as possible
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158 finaltags.sort(key=operator.itemgetter(0))
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159
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160 # finally we can join the sorted groups to get the final contents of the
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161 # merged .hgtags file, and then write it to disk
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162 mergedtagstring = '\n'.join([tags for rank, tags in finaltags if tags])
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163 fp = repo.wfile('.hgtags', 'wb')
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164 fp.write(mergedtagstring + '\n')
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165 fp.close()
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166
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167 def singletagmerge(p1nodes, p2nodes):
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168 '''
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169 merge the nodes corresponding to a single tag
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170
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171 Note that the inputs are lists of node-linenum pairs (i.e. not just lists
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172 of nodes)
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173 '''
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174 if not p2nodes:
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175 return p1nodes
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176 if not p1nodes:
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177 return p2nodes
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178
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179 # there is no conflict unless both tags point to different revisions
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180 # and have a non identical tag history
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181 p1currentnode = p1nodes[-1][0]
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182 p2currentnode = p2nodes[-1][0]
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183 if p1currentnode != p2currentnode and len(p1nodes) == len(p2nodes):
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184 # cannot merge two tags with same rank pointing to different nodes
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185 return None
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186
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187 # which are the highest ranking (hr) / lowest ranking (lr) nodes?
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188 if len(p1nodes) >= len(p2nodes):
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189 hrnodes, lrnodes = p1nodes, p2nodes
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190 else:
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191 hrnodes, lrnodes = p2nodes, p1nodes
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192
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193 # the lowest ranking nodes will be written first, followed by the highest
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194 # ranking nodes
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195 # to avoid unwanted tag rank explosion we try to see if there are some
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196 # common nodes that can be written only once
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197 commonidx = len(lrnodes)
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198 for n in range(len(lrnodes)):
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199 if hrnodes[n][0] != lrnodes[n][0]:
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200 commonidx = n
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201 break
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202 lrnodes[n][1] = p1nodes[n][1]
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203
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204 # the merged node list has 3 parts:
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205 # - common nodes
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206 # - non common lowest ranking nodes
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207 # - non common highest ranking nodes
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208 # note that the common nodes plus the non common lowest ranking nodes is the
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209 # whole list of lr nodes
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210 return lrnodes + hrnodes[commonidx:]
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211
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212 def merge(repo, fcd, fco, fca):
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213 '''
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214 Merge the tags of two revisions, taking into account the base tags
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215 Try to minimize the diff between the merged tags and the first parent tags
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216 '''
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217 ui = repo.ui
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218 # read the p1, p2 and base tags
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219 # only keep the line numbers for the p1 tags
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220 p1tags = readtagsformerge(
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221 ui, repo, fcd.data().splitlines(), fn="p1 tags",
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222 keeplinenums=True)
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223 p2tags = readtagsformerge(
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224 ui, repo, fco.data().splitlines(), fn="p2 tags",
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225 keeplinenums=False)
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226 basetags = readtagsformerge(
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227 ui, repo, fca.data().splitlines(), fn="base tags",
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228 keeplinenums=False)
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229
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230 # recover the list of "lost tags" (i.e. those that were found on the base
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231 # revision but not on one of the revisions being merged)
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232 basetagset = set(basetags)
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233 for n, pntags in enumerate((p1tags, p2tags)):
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234 pntagset = set(pntags)
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235 pnlosttagset = basetagset - pntagset
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236 for t in pnlosttagset:
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237 pntags[t] = basetags[t]
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238 if pntags[t][-1][0] != hexnullid:
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239 pntags[t].append([hexnullid, None])
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240
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241 conflictedtags = [] # for reporting purposes
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242 mergedtags = util.sortdict(p1tags)
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243 # sortdict does not implement iteritems()
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244 for tname, p2nodes in p2tags.items():
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245 if tname not in mergedtags:
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246 mergedtags[tname] = p2nodes
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247 continue
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248 p1nodes = mergedtags[tname]
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249 mergednodes = singletagmerge(p1nodes, p2nodes)
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250 if mergednodes is None:
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251 conflictedtags.append(tname)
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252 continue
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253 mergedtags[tname] = mergednodes
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254
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255 if conflictedtags:
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256 numconflicts = len(conflictedtags)
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257 ui.warn(_('automatic .hgtags merge failed\n'
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258 'the following %d tags are in conflict: %s\n')
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259 % (numconflicts, ', '.join(sorted(conflictedtags))))
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260 return True, 1
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261
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262 writemergedtags(repo, mergedtags)
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263 ui.note(_('.hgtags merged successfully\n'))
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264 return False, 0
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265