Mercurial > hg

comparison mercurial/help.py @ 26370:44cc9f63a2f1

Find changesets by keywords (author, files, the commit message), revision number or hash, or revset expression.
help: include parens in DEPRECATED/EXPERIMENTAL keywords In some languages that have no caps, "DEPRECATED" and "deprecated" can be translated to the same byte sequence. So it is too wild to exclude messages by _("DEPRECATED").
author Yuya Nishihara <yuya@tcha.org>
date Sat, 26 Sep 2015 11:38:39 +0900
parents 4799b5c4aaf4
children 51b309ce6c7d
comparison
equal deleted inserted replaced
26369:4799b5c4aaf4 26370:44cc9f63a2f1
13 import encoding, util, minirst 13 import encoding, util, minirst
14 import cmdutil 14 import cmdutil
15 import hgweb.webcommands as webcommands 15 import hgweb.webcommands as webcommands
16 16
17 _exclkeywords = [ 17 _exclkeywords = [
18 "DEPRECATED", 18 "(DEPRECATED)",
19 "EXPERIMENTAL", 19 "(EXPERIMENTAL)",
20 _("DEPRECATED"), 20 # i18n: "(DEPRECATED)" is a keyword, must be translated consistently
21 _("EXPERIMENTAL"), 21 _("(DEPRECATED)"),
22 # i18n: "(EXPERIMENTAL)" is a keyword, must be translated consistently
23 _("(EXPERIMENTAL)"),
22 ] 24 ]
23 25
24 def listexts(header, exts, indent=1, showdeprecated=False): 26 def listexts(header, exts, indent=1, showdeprecated=False):
25 '''return a text listing of the given extensions''' 27 '''return a text listing of the given extensions'''
26 rst = [] 28 rst = []
337 continue 339 continue
338 f = f.lstrip("^") 340 f = f.lstrip("^")
339 if not ui.debugflag and f.startswith("debug") and name != "debug": 341 if not ui.debugflag and f.startswith("debug") and name != "debug":
340 continue 342 continue
341 doc = e[0].__doc__ 343 doc = e[0].__doc__
342 if doc and 'DEPRECATED' in doc and not ui.verbose: 344 if doc and '(DEPRECATED)' in doc and not ui.verbose:
343 continue 345 continue
344 doc = gettext(doc) 346 doc = gettext(doc)
345 if not doc: 347 if not doc:
346 doc = _("(no help text available)") 348 doc = _("(no help text available)")
347 h[f] = doc.splitlines()[0].rstrip() 349 h[f] = doc.splitlines()[0].rstrip()