comparison mercurial/revset.py @ 23724:aafeaba22826 stable

revset: drop pre-lazyset optimization for stringset of subset == entire repo It was introduced at e44ebd2a142a, where spanset.__contains__() did not exist. Nowadays, we have to pay huge penalty for len(subset). The following example showed that OR operation could be O(n * m^2) (n: len(repo), m: number of OR operators, m >= 2) probably because of filteredset.__len__. revset #0: 0|1|2|3|4|5|6|7|8|9 0) wall 8.092713 comb 8.090000 user 8.090000 sys 0.000000 (best of 3) 1) wall 0.445354 comb 0.450000 user 0.430000 sys 0.020000 (best of 22) 2) wall 0.000389 comb 0.000000 user 0.000000 sys 0.000000 (best of 7347) (0: 3.2.4, 1: 3.1.2, 2: this patch)
author Yuya Nishihara <yuya@tcha.org>
date Sat, 03 Jan 2015 10:25:08 +0900
parents 0c432696dae3
children d944492445fa c90d195320c5
comparison
equal deleted inserted replaced
23721:1b3df5ef5949 23724:aafeaba22826
253 253
254 def stringset(repo, subset, x): 254 def stringset(repo, subset, x):
255 x = repo[x].rev() 255 x = repo[x].rev()
256 if x == -1 and len(subset) == len(repo): 256 if x == -1 and len(subset) == len(repo):
257 return baseset([-1]) 257 return baseset([-1])
258 if len(subset) == len(repo) or x in subset: 258 if x in subset:
259 return baseset([x]) 259 return baseset([x])
260 return baseset() 260 return baseset()
261 261
262 def symbolset(repo, subset, x): 262 def symbolset(repo, subset, x):
263 if x in symbols: 263 if x in symbols: