comparison mercurial/revlog.py @ 224:ccbcc4d76f81

fix bad assumption about uniqueness of file versions

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Hash: SHA1

fix bad assumption about uniqueness of file versions

Mercurial had assumed that a given file hash could show up in only one
changeset, and thus that the mapping from file revision to changeset
was 1-to-1. But if two people perform the same edit with the same
parents, we can get an identical hash in different changesets.

So we've got to loosen up our uniqueness checks in addgroup and in
verify.

manifest hash: 5462003241e7d071ffa1741b87a59f646c9988ed
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223:1aaa49039a6b

            yield meta
            yield d

        yield struct.pack(">l", 0)

    def addgroup(self, revs, linkmapper, transaction):
        # given a set of deltas, add them to the revision log. the
        # first delta is against its parent, which should be in our
        # log, the rest are against the previous delta.

        # track the base of the current delta log

        chain = None
        for chunk in revs:
            node, p1, p2, cs = struct.unpack("20s20s20s20s", chunk[:80])
            link = linkmapper(cs)
            if node in self.nodemap:
                raise "already have %s" % hex(node[:4])
            delta = chunk[80:]

            if not chain:
                # retrieve the parent revision of the delta chain
                chain = p1

224:ccbcc4d76f81

            yield meta
            yield d

        yield struct.pack(">l", 0)

    def addgroup(self, revs, linkmapper, transaction, unique = 0):
        # given a set of deltas, add them to the revision log. the
        # first delta is against its parent, which should be in our
        # log, the rest are against the previous delta.

        # track the base of the current delta log

        chain = None
        for chunk in revs:
            node, p1, p2, cs = struct.unpack("20s20s20s20s", chunk[:80])
            link = linkmapper(cs)
            if node in self.nodemap:
                # this can happen if two branches make the same change
                if unique:
                    raise "already have %s" % hex(node[:4])
                continue
            delta = chunk[80:]

            if not chain:
                # retrieve the parent revision of the delta chain
                chain = p1