comparison mercurial/copies.py @ 6277:cfebb175704f

copies: deal with symmetric difference for linear relationships choose the minimum of symmetric difference and the two revs in question
author Matt Mackall <mpm@selenic.com>
date Sat, 15 Mar 2008 16:25:27 -0500
parents fda369b5779c
children 5a45c82fc7da
comparison
equal deleted inserted replaced
6276:c93ca83a3354 6277:cfebb175704f
66 if rev2 is None: # c2 is a workingctx 66 if rev2 is None: # c2 is a workingctx
67 rev2 = c2.parents()[0].rev() 67 rev2 = c2.parents()[0].rev()
68 pr = repo.changelog.parentrevs 68 pr = repo.changelog.parentrevs
69 def parents(rev): 69 def parents(rev):
70 return [p for p in pr(rev) if p != nullrev] 70 return [p for p in pr(rev) if p != nullrev]
71 limit = min(ancestor.symmetricdifference(rev1, rev2, parents)) 71 limit = min(ancestor.symmetricdifference(rev1, rev2, parents) + [rev1, rev2])
72 m1 = c1.manifest() 72 m1 = c1.manifest()
73 m2 = c2.manifest() 73 m2 = c2.manifest()
74 ma = ca.manifest() 74 ma = ca.manifest()
75 75
76 def makectx(f, n): 76 def makectx(f, n):