diff mercurial/parsers.c @ 20555:4add43865a9b

ancestors: remove unnecessary handling of 'left'

If one of the initial nodes also is an ancestor then that most be the only
ancestor. There is no need for additional bookkeeping.

--- a/mercurial/parsers.c	Mon Feb 24 22:42:13 2014 +0100
+++ b/mercurial/parsers.c	Mon Feb 24 22:42:13 2014 +0100
@@ -1208,7 +1208,7 @@
 	const bitmask allseen = (1ull << revcount) - 1;
 	const bitmask poison = 1ull << revcount;
 	PyObject *gca = PyList_New(0);
-	int i, v, interesting, left;
+	int i, v, interesting;
 	int maxrev = -1;
 	long sp;
 	bitmask *seen;
@@ -1230,7 +1230,7 @@
 	for (i = 0; i < revcount; i++)
 		seen[revs[i]] = 1ull << i;
 
-	interesting = left = revcount;
+	interesting = revcount;
 
 	for (v = maxrev; v >= 0 && interesting; v--) {
 		long sv = seen[v];
@@ -1251,11 +1251,8 @@
 				}
 				sv |= poison;
 				for (i = 0; i < revcount; i++) {
-					if (revs[i] == v) {
-						if (--left <= 1)
-							goto done;
-						break;
-					}
+					if (revs[i] == v)
+						goto done;
 				}
 			}
 		}