diff mercurial/hbisect.py @ 6858:8f256bf98219

Add support for multiple possible bisect results (issue1228, issue1182) The real reason for both issue is that bisect can not handle cases where there are multiple possibilities for the result. Example (from issue1228): rev 0 -> good rev 1 -> skipped rev 2 -> skipped rev 3 -> skipped rev 4 -> bad Note that this patch does not only fix the reported Assertion Error but also the problem of a non converging bisect: hg init for i in `seq 3`; do echo $i > $i; hg add $i; hg ci -m$i; done hg bisect -b 2 hg bisect -g 0 hg bisect -s From this state on, you can: a) mark as bad forever (non converging!) b) mark as good to get an inconsistent state c) skip for the Assertion Error Minor description and code edits by pmezard.
author Bernhard Leiner <bleiner@gmail.com>
date Sat, 02 Aug 2008 22:10:10 +0200
parents fe8dbbe9520d
children 0b6f2fa5e03f
line wrap: on
line diff
--- a/mercurial/hbisect.py	Tue Jul 15 18:10:37 2008 -0500
+++ b/mercurial/hbisect.py	Sat Aug 02 22:10:10 2008 +0200
@@ -12,6 +12,16 @@
 import util
 
 def bisect(changelog, state):
+    """find the next node (if any) for testing during a bisect search.
+    returns a (nodes, number, good) tuple.
+
+    'nodes' is the final result of the bisect if 'number' is 0.
+    Otherwise 'number' indicates the remaining possible candidates for
+    the search and 'nodes' contains the next bisect target.
+    'good' is True if bisect is searching for a first good changeset, False
+    if searching for a first bad one.
+    """
+
     clparents = changelog.parentrevs
     skip = dict.fromkeys([changelog.rev(n) for n in state['skip']])
 
@@ -62,9 +72,11 @@
 
     candidates.sort()
     # have we narrowed it down to one entry?
+    # or have all other possible candidates besides 'bad' have been skipped?
     tot = len(candidates)
-    if tot == 1:
-        return (bad, 0, good)
+    unskipped = [c for c in candidates if (c not in skip) and (c != badrev)]
+    if tot == 1 or not unskipped:
+        return ([changelog.node(rev) for rev in candidates], 0, good)
     perfect = tot / 2
 
     # find the best node to test
@@ -103,4 +115,4 @@
     assert best_rev is not None
     best_node = changelog.node(best_rev)
 
-    return (best_node, tot, good)
+    return ([best_node], tot, good)