revlog: use node tree (native code) for shortest() calculation
I want to rewrite revlog.shortest() to disambiguate only among hex
nodeids and then disambiguate the result with revnums at a higher
level (in scmutil). However, that would slow down `hg log -T
'{shortest(node,1)}\n'` from 5.0s to 6.8s, which I wasn't sure would
be acceptable. So this patch makes revlog.shortest() use the node tree
for finding the length of the shortest prefix that's unambiguous among
nodeids. Once that has been found, it makes it longer until it is also
not ambiguous with a revnum.
This speeds up `hg log -T '{shortest(node,1)}\n'` from 5.0s to 4.0s.
Differential Revision: https://phab.mercurial-scm.org/D3499
from __future__ import absolute_import
import os
import time
class mocktime(object):
def __init__(self, increment):
self.time = 0
self.increment = [float(s) for s in increment.split()]
self.pos = 0
def __call__(self):
self.time += self.increment[self.pos % len(self.increment)]
self.pos += 1
return self.time
def uisetup(ui):
time.time = mocktime(os.environ.get('MOCKTIME', '0.1'))