Mercurial > hg
view tests/test-demandimport.py @ 17970:0b03454abae7
ancestor: faster algorithm for difference of ancestor sets
One of the major reasons rebase is slow in large repositories is
the computation of the detach set: the set of ancestors of the
changesets to rebase not in the destination parent. This is currently
done via a revset that does two walks all the way to the root of
the DAG. Instead of doing that, to find ancestors of a set <revs>
not in another set <common> we walk up the tree in reverse revision
number order, maintaining sets of nodes visited from <revs>, <common>
or both.
For the common case where the sets are close both topologically and
in revision number (relative to repository size), this has been
found to speed up rebase by around 15-20%. When the nodes are farther
apart and the DAG is highly branching, it is harder to say which
would win.
Here's how long computing the detach set takes in a linear repository
with over 400000 changesets, rebasing near tip:
Rebasing across 4 changesets
Revset method: 2.2s
New algorithm: 0.00015s
Rebasing across 250 changesets
Revset method: 2.2s
New algorithm: 0.00069s
Rebasing across 10000 changesets
Revset method: 2.4s
New algorithm: 0.019s
author | Siddharth Agarwal <sid0@fb.com> |
---|---|
date | Mon, 26 Nov 2012 11:46:51 -0800 |
parents | c0290fc6b486 |
children | 54af51c18c4c |
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from mercurial import demandimport demandimport.enable() import re rsub = re.sub def f(obj): l = repr(obj) l = rsub("0x[0-9a-fA-F]+", "0x?", l) l = rsub("from '.*'", "from '?'", l) l = rsub("'<[a-z]*>'", "'<whatever>'", l) return l import os print "os =", f(os) print "os.system =", f(os.system) print "os =", f(os) from mercurial import util print "util =", f(util) print "util.system =", f(util.system) print "util =", f(util) print "util.system =", f(util.system) import re as fred print "fred =", f(fred) import sys as re print "re =", f(re) print "fred =", f(fred) print "fred.sub =", f(fred.sub) print "fred =", f(fred) print "re =", f(re) print "re.stderr =", f(re.stderr) print "re =", f(re)