Mercurial > hg
view mercurial/pure/base85.py @ 13550:1792b8a9422b stable
merge: back out single-parent fast-forward merge
This backs out
changeset: 13158:9e7e24052745
user: Mads Kiilerich <mads@kiilerich.com>
date: Tue Dec 07 03:29:21 2010 +0100
summary: merge: fast-forward merge with descendant
Before named branches, the invariants were:
a) "merges" always have two parents
b) p1 is not linearly related to p2
Adding named branches made (b) problematic, so the above patch was
introduced, which fixed (b) but broke (a).
After discussion, we decided that the invariants should be:
a) "merges" always have two parents
b) p1 is not linearly related to p2 OR p1 and p2 are on different branches
author | Matt Mackall <mpm@selenic.com> |
---|---|
date | Mon, 07 Mar 2011 15:03:10 -0600 |
parents | 08a0f04b56bd |
children | 20a9d823f242 |
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# base85.py: pure python base85 codec # # Copyright (C) 2009 Brendan Cully <brendan@kublai.com> # # This software may be used and distributed according to the terms of the # GNU General Public License version 2 or any later version. import struct _b85chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" \ "abcdefghijklmnopqrstuvwxyz!#$%&()*+-;<=>?@^_`{|}~" _b85chars2 = [(a + b) for a in _b85chars for b in _b85chars] _b85dec = {} def _mkb85dec(): for i, c in enumerate(_b85chars): _b85dec[c] = i def b85encode(text, pad=False): """encode text in base85 format""" l = len(text) r = l % 4 if r: text += '\0' * (4 - r) longs = len(text) >> 2 words = struct.unpack('>%dL' % (longs), text) out = ''.join(_b85chars[(word // 52200625) % 85] + _b85chars2[(word // 7225) % 7225] + _b85chars2[word % 7225] for word in words) if pad: return out # Trim padding olen = l % 4 if olen: olen += 1 olen += l // 4 * 5 return out[:olen] def b85decode(text): """decode base85-encoded text""" if not _b85dec: _mkb85dec() l = len(text) out = [] for i in range(0, len(text), 5): chunk = text[i:i + 5] acc = 0 for j, c in enumerate(chunk): try: acc = acc * 85 + _b85dec[c] except KeyError: raise TypeError('Bad base85 character at byte %d' % (i + j)) if acc > 4294967295: raise OverflowError('Base85 overflow in hunk starting at byte %d' % i) out.append(acc) # Pad final chunk if necessary cl = l % 5 if cl: acc *= 85 ** (5 - cl) if cl > 1: acc += 0xffffff >> (cl - 2) * 8 out[-1] = acc out = struct.pack('>%dL' % (len(out)), *out) if cl: out = out[:-(5 - cl)] return out