Mercurial > hg
view tests/test-glog-topological.t @ 41152:191fac9ff9d3
obsutil: fix the issue5686
While traversing the obsolescence graph to find the successors sets
of csets:
In its 4th case (read comments of obsutil.successorssets to see
all 4 cases) where we know successors sets of all direct successors
of CURRENT, we were just missing a condition to filter out the case
when a cset is pruned.
And without this condition (that this patch added) it was making a whole
successor set to [] just because of one pruned marker.
For e.g:if following is the successors set of a cset A:
A -> [a, b, c]
if we prune c, we expect A's successors set to be [a, b] but
you would get:
A -> []
So this patch make sure that we calculate the right successorsset of csets
considering the pruned cset (in split case).
Differential Revision: https://phab.mercurial-scm.org/D5474
author | Sushil khanchi <sushilkhanchi97@gmail.com> |
---|---|
date | Sun, 23 Dec 2018 02:01:35 +0530 |
parents | 89630d0b3e23 |
children | 604c086ddde6 |
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This test file aims at test topological iteration and the various configuration it can has. $ cat >> $HGRCPATH << EOF > [ui] > logtemplate={rev}\n > EOF On this simple example, all topological branch are displayed in turn until we can finally display 0. this implies skipping from 8 to 3 and coming back to 7 later. $ hg init test01 $ cd test01 $ hg unbundle $TESTDIR/bundles/remote.hg adding changesets adding manifests adding file changes added 9 changesets with 7 changes to 4 files (+1 heads) new changesets bfaf4b5cbf01:916f1afdef90 (9 drafts) (run 'hg heads' to see heads, 'hg merge' to merge) $ hg log -G o 8 | | o 7 | | | o 6 | | | o 5 | | | o 4 | | o | 3 | | o | 2 | | o | 1 |/ o 0 (display all nodes) $ hg log -G -r 'sort(all(), topo)' o 8 | o 3 | o 2 | o 1 | | o 7 | | | o 6 | | | o 5 | | | o 4 |/ o 0 (display nodes filtered by log options) $ hg log -G -r 'sort(all(), topo)' -k '.3' o 8 | o 3 | ~ o 7 | o 6 | ~ (revset skipping nodes) $ hg log -G --rev 'sort(not (2+6), topo)' o 8 | o 3 : o 1 | | o 7 | : | o 5 | | | o 4 |/ o 0 (begin) from the other branch $ hg log -G -r 'sort(all(), topo, topo.firstbranch=5)' o 7 | o 6 | o 5 | o 4 | | o 8 | | | o 3 | | | o 2 | | | o 1 |/ o 0