view tests/test-glog-topological.t @ 36863:1a1972b1a1ff

hgweb: use our new request object for "style" parameter

The "style" parameter is kind of wonky because it is explicitly
set and has lookups in random locations.

Let's port it to qsparams first because it isn't straightforward.

There is subtle change in behavior. But I don't think it is worth
calling out in a BC.

Our multidict's __getitem__ returns the last set value for a key,
not the first. So if the query string set a variable multiple times,
before we would get the first value and now we would get the last
value. It makes no sense to specify these things multiple times.
And I think last write wins is more sensible than first write wins.

Differential Revision: https://phab.mercurial-scm.org/D2779

This test file aims at test topological iteration and the various configuration it can has.

  $ cat >> $HGRCPATH << EOF
  > [ui]
  > logtemplate={rev}\n
  > EOF

On this simple example, all topological branch are displayed in turn until we
can finally display 0. this implies skipping from 8 to 3 and coming back to 7
later.

  $ hg init test01
  $ cd test01
  $ hg unbundle $TESTDIR/bundles/remote.hg
  adding changesets
  adding manifests
  adding file changes
  added 9 changesets with 7 changes to 4 files (+1 heads)
  new changesets bfaf4b5cbf01:916f1afdef90
  (run 'hg heads' to see heads, 'hg merge' to merge)

  $ hg log -G
  o  8
  |
  | o  7
  | |
  | o  6
  | |
  | o  5
  | |
  | o  4
  | |
  o |  3
  | |
  o |  2
  | |
  o |  1
  |/
  o  0
  

(display all nodes)

  $ hg log -G -r 'sort(all(), topo)'
  o  8
  |
  o  3
  |
  o  2
  |
  o  1
  |
  | o  7
  | |
  | o  6
  | |
  | o  5
  | |
  | o  4
  |/
  o  0
  

(display nodes filtered by log options)

  $ hg log -G -r 'sort(all(), topo)' -k '.3'
  o  8
  |
  o  3
  |
  ~
  o  7
  |
  o  6
  |
  ~

(revset skipping nodes)

  $ hg log -G --rev 'sort(not (2+6), topo)'
  o  8
  |
  o  3
  :
  o  1
  |
  | o  7
  | :
  | o  5
  | |
  | o  4
  |/
  o  0
  

(begin) from the other branch

  $ hg log -G -r 'sort(all(), topo, topo.firstbranch=5)'
  o  7
  |
  o  6
  |
  o  5
  |
  o  4
  |
  | o  8
  | |
  | o  3
  | |
  | o  2
  | |
  | o  1
  |/
  o  0