view tests/test-lrucachedict.py @ 28240:1ac8ce137377

changegroup: fix treemanifests on merges

The current code for generating treemanifest revisions takes the list
of files in the changeset and finds the directories from them. This
does not work for merges, since a merge may pick file A from one side
and file B from another and neither of them would appear in the
changeset's "files" list, but the manifest would still change.

Fix this by instead walking the root manifest log for all needed
revisions, storing all needed file and subdirectory revisions, then
recursively visiting the subdirectories. This also turns out to be
faster: cloning a version of hg core converted to treemanifests went
from ~28s to ~19s (timing somewhat unfair: before this patch, timed
until crash; after this patch, timed until manifests complete).

The new algorithm is used only on treemanifest repos. Although it
works equally well on flat manifests, we leave the iteration over
files in the changeset for flat manifests for now.

from mercurial import util

def printifpresent(d, xs, name='d'):
    for x in xs:
        present = x in d
        print "'%s' in %s: %s" % (x, name, present)
        if present:
            print "%s['%s']: %s" % (name, x, d[x])

def test_lrucachedict():
    d = util.lrucachedict(4)
    d['a'] = 'va'
    d['b'] = 'vb'
    d['c'] = 'vc'
    d['d'] = 'vd'

    # all of these should be present
    printifpresent(d, ['a', 'b', 'c', 'd'])

    # 'a' should be dropped because it was least recently used
    d['e'] = 've'
    printifpresent(d, ['a', 'b', 'c', 'd', 'e'])

    # touch entries in some order (get or set).
    d['e']
    d['c'] = 'vc2'
    d['d']
    d['b'] = 'vb2'

    # 'e' should be dropped now
    d['f'] = 'vf'
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

    d.clear()
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

    # Now test dicts that aren't full.
    d = util.lrucachedict(4)
    d['a'] = 1
    d['b'] = 2
    d['a']
    d['b']
    printifpresent(d, ['a', 'b'])

    # test copy method
    d = util.lrucachedict(4)
    d['a'] = 'va3'
    d['b'] = 'vb3'
    d['c'] = 'vc3'
    d['d'] = 'vd3'

    dc = d.copy()

    # all of these should be present
    print "\nAll of these should be present:"
    printifpresent(dc, ['a', 'b', 'c', 'd'], 'dc')

    # 'a' should be dropped because it was least recently used
    print "\nAll of these except 'a' should be present:"
    dc['e'] = 've3'
    printifpresent(dc, ['a', 'b', 'c', 'd', 'e'], 'dc')

    # contents and order of original dict should remain unchanged
    print "\nThese should be in reverse alphabetical order and read 'v?3':"
    dc['b'] = 'vb3_new'
    for k in list(iter(d)):
        print "d['%s']: %s" % (k, d[k])

if __name__ == '__main__':
    test_lrucachedict()