Mercurial > hg
view tests/test-lrucachedict.py @ 20275:2123d27ff75d
backout: avoid update on simple case.
Before the changeset the backout process was:
1) go to <target>
2) revert to <target> parent
3) update back to changeset we came from
The two update steps can takes a very long time to move back and forth unrelated
file change between <target> and current working directory.
The new process is just merging current working directory with the parent of
<target> using <target> as ancestor. This give the very same result but skip
the two updates. On big repo with a lot of files and changes that save a lots of
time (x20 for one week window).
The "merge" version (hg backout --merge) is still done with upgrades. We could
imagine using in memory commit to speed it up but this is another fish.
author | Pierre-Yves David <pierre-yves.david@fb.com> |
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date | Wed, 08 Jan 2014 14:53:46 -0800 |
parents | 887ffa22fd0d |
children | 45d996a566d7 |
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from mercurial import util def printifpresent(d, xs): for x in xs: present = x in d print "'%s' in d: %s" % (x, present) if present: print "d['%s']: %s" % (x, d[x]) def test_lrucachedict(): d = util.lrucachedict(4) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' d['d'] = 'vd' # all of these should be present printifpresent(d, ['a', 'b', 'c', 'd']) # 'a' should be dropped because it was least recently used d['e'] = 've' printifpresent(d, ['a', 'b', 'c', 'd', 'e']) # touch entries in some order (get or set). d['e'] d['c'] = 'vc2' d['d'] d['b'] = 'vb2' # 'e' should be dropped now d['f'] = 'vf' printifpresent(d, ['b', 'c', 'd', 'e', 'f']) d.clear() printifpresent(d, ['b', 'c', 'd', 'e', 'f']) if __name__ == '__main__': test_lrucachedict()