view tests/test-lrucachedict.py @ 20275:2123d27ff75d

backout: avoid update on simple case. Before the changeset the backout process was: 1) go to <target> 2) revert to <target> parent 3) update back to changeset we came from The two update steps can takes a very long time to move back and forth unrelated file change between <target> and current working directory. The new process is just merging current working directory with the parent of <target> using <target> as ancestor. This give the very same result but skip the two updates. On big repo with a lot of files and changes that save a lots of time (x20 for one week window). The "merge" version (hg backout --merge) is still done with upgrades. We could imagine using in memory commit to speed it up but this is another fish.
author Pierre-Yves David <pierre-yves.david@fb.com>
date Wed, 08 Jan 2014 14:53:46 -0800
parents 887ffa22fd0d
children 45d996a566d7
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from mercurial import util

def printifpresent(d, xs):
    for x in xs:
        present = x in d
        print "'%s' in d: %s" % (x, present)
        if present:
            print "d['%s']: %s" % (x, d[x])

def test_lrucachedict():
    d = util.lrucachedict(4)
    d['a'] = 'va'
    d['b'] = 'vb'
    d['c'] = 'vc'
    d['d'] = 'vd'

    # all of these should be present
    printifpresent(d, ['a', 'b', 'c', 'd'])

    # 'a' should be dropped because it was least recently used
    d['e'] = 've'
    printifpresent(d, ['a', 'b', 'c', 'd', 'e'])

    # touch entries in some order (get or set).
    d['e']
    d['c'] = 'vc2'
    d['d']
    d['b'] = 'vb2'

    # 'e' should be dropped now
    d['f'] = 'vf'
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

    d.clear()
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

if __name__ == '__main__':
    test_lrucachedict()