backout: avoid update on simple case.
Before the changeset the backout process was:
1) go to <target>
2) revert to <target> parent
3) update back to changeset we came from
The two update steps can takes a very long time to move back and forth unrelated
file change between <target> and current working directory.
The new process is just merging current working directory with the parent of
<target> using <target> as ancestor. This give the very same result but skip
the two updates. On big repo with a lot of files and changes that save a lots of
time (x20 for one week window).
The "merge" version (hg backout --merge) is still done with upgrades. We could
imagine using in memory commit to speed it up but this is another fish.
from mercurial import wireproto
class proto(object):
def __init__(self, args):
self.args = args
def getargs(self, spec):
args = self.args
args.setdefault('*', {})
names = spec.split()
return [args[n] for n in names]
class clientpeer(wireproto.wirepeer):
def __init__(self, serverrepo):
self.serverrepo = serverrepo
def _call(self, cmd, **args):
return wireproto.dispatch(self.serverrepo, proto(args), cmd)
@wireproto.batchable
def greet(self, name):
f = wireproto.future()
yield wireproto.todict(name=mangle(name)), f
yield unmangle(f.value)
class serverrepo(object):
def greet(self, name):
return "Hello, " + name
def filtered(self, name):
return self
def mangle(s):
return ''.join(chr(ord(c) + 1) for c in s)
def unmangle(s):
return ''.join(chr(ord(c) - 1) for c in s)
def greet(repo, proto, name):
return mangle(repo.greet(unmangle(name)))
wireproto.commands['greet'] = (greet, 'name',)
srv = serverrepo()
clt = clientpeer(srv)
print clt.greet("Foobar")
b = clt.batch()
fs = [b.greet(s) for s in ["Fo, =;o", "Bar"]]
b.submit()
print [f.value for f in fs]