view mercurial/dicthelpers.py @ 21543:21b3513d43e4 stable

proxy: remove unneeded _set_hostport for compatibility with Python 2.7.7rc1 With Python 2.7.7rc1, "hg pull" through HTTP CONNECT tunnel fails due to the removal of _set_hostport [1]. ... File "mercurial/url.py", line 372, in https_open return self.do_open(self._makeconnection, req) ... File "mercurial/url.py", line 342, in connect _generic_proxytunnel(self) File "mercurial/url.py", line 228, in _generic_proxytunnel self._set_hostport(self.host, self.port) AttributeError: httpsconnection instance has no attribute '_set_hostport' self._set_hostport(self.host, self.port) should be noop and can be removed because: - _set_hostport() [2] was the function to parse "host:port" string and set them to self.host and self.port, - and (self.host, self.port) pair should be valid since connect() is called prior to _generic_proxytunnel(). [1]: http://hg.python.org/cpython/rev/568041fd8090 [2]: http://hg.python.org/cpython/file/3a1db0d2747e/Lib/httplib.py#l721
author Yuya Nishihara <yuya@tcha.org>
date Thu, 22 May 2014 22:05:26 +0900
parents ed46c2b98b0d
children
line wrap: on
line source

# dicthelpers.py - helper routines for Python dicts
#
# Copyright 2013 Facebook
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.

def diff(d1, d2, default=None):
    '''Return all key-value pairs that are different between d1 and d2.

    This includes keys that are present in one dict but not the other, and
    keys whose values are different. The return value is a dict with values
    being pairs of values from d1 and d2 respectively, and missing values
    treated as default, so if a value is missing from one dict and the same as
    default in the other, it will not be returned.'''
    res = {}
    if d1 is d2:
        # same dict, so diff is empty
        return res

    for k1, v1 in d1.iteritems():
        v2 = d2.get(k1, default)
        if v1 != v2:
            res[k1] = (v1, v2)

    for k2 in d2:
        if k2 not in d1:
            v2 = d2[k2]
            if v2 != default:
                res[k2] = (default, v2)

    return res

def join(d1, d2, default=None):
    '''Return all key-value pairs from both d1 and d2.

    This is akin to an outer join in relational algebra. The return value is a
    dict with values being pairs of values from d1 and d2 respectively, and
    missing values represented as default.'''
    res = {}

    for k1, v1 in d1.iteritems():
        if k1 in d2:
            res[k1] = (v1, d2[k1])
        else:
            res[k1] = (v1, default)

    if d1 is d2:
        return res

    for k2 in d2:
        if k2 not in d1:
            res[k2] = (default, d2[k2])

    return res