Mercurial > hg
view tests/test-glog-topological.t @ 35115:2b72bc88043f
bundle2: only seek to beginning of part in bundlerepo
For reasons still not yet fully understood by me, bundlerepo
requires its changegroup bundle2 part to be seeked to beginning
after part iteration. As far as I can tell, it is the only
bundle2 part consumer that relies on this behavior.
This seeking was performed in the generic iterparts() API. Again,
I don't fully understand why it was here and not in bundlerepo.
Probably historical reasons.
What I do know is that all other bundle2 part consumers don't
need this special behavior (assuming the tests are comprehensive).
So, we move the code from bundle2's iterparts() to bundlerepo's
consumption of iterparts().
Differential Revision: https://phab.mercurial-scm.org/D1389
author | Gregory Szorc <gregory.szorc@gmail.com> |
---|---|
date | Mon, 13 Nov 2017 20:12:00 -0800 |
parents | eb586ed5d8ce |
children | 89630d0b3e23 |
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This test file aims at test topological iteration and the various configuration it can has. $ cat >> $HGRCPATH << EOF > [ui] > logtemplate={rev}\n > EOF On this simple example, all topological branch are displayed in turn until we can finally display 0. this implies skipping from 8 to 3 and coming back to 7 later. $ hg init test01 $ cd test01 $ hg unbundle $TESTDIR/bundles/remote.hg adding changesets adding manifests adding file changes added 9 changesets with 7 changes to 4 files (+1 heads) new changesets bfaf4b5cbf01:916f1afdef90 (run 'hg heads' to see heads, 'hg merge' to merge) $ hg log -G o 8 | | o 7 | | | o 6 | | | o 5 | | | o 4 | | o | 3 | | o | 2 | | o | 1 |/ o 0 (display all nodes) $ hg log -G -r 'sort(all(), topo)' o 8 | o 3 | o 2 | o 1 | | o 7 | | | o 6 | | | o 5 | | | o 4 |/ o 0 (display nodes filtered by log options) $ hg log -G -r 'sort(all(), topo)' -k '.3' o 8 | o 3 | ~ o 7 | o 6 | ~ (revset skipping nodes) $ hg log -G --rev 'sort(not (2+6), topo)' o 8 | o 3 : o 1 | | o 7 | : | o 5 | | | o 4 |/ o 0 (begin) from the other branch $ hg log -G -r 'sort(all(), topo, topo.firstbranch=5)' o 7 | o 6 | o 5 | o 4 | | o 8 | | | o 3 | | | o 2 | | | o 1 |/ o 0