revset: fix order of nested 'or' expression (BC)
This fixes the order of 'x & (y + z)' where 'y' and 'z' are not trivial.
The follow-order 'or' operation is slower than the ordered operation if
an input set is large:
#0 #1 #2 #3
0) 0.002968 0.002980 0.002982 0.073042
1) 0.004513 0.004485 0.012029 0.075261
#0: 0:4000 & (0:1099 + 1000:2099 + 2000:3099)
#1: 4000:0 & (0:1099 + 1000:2099 + 2000:3099)
#2: 10000:0 & (0:1099 + 1000:2099 + 2000:3099)
#3: file("path:hg") & (0:1099 + 1000:2099 + 2000:3099)
I've tried another implementation, but which appeared to be slower than
this version.
ss = [getset(repo, fullreposet(repo), x) for x in xs]
return subset.filter(lambda r: any(r in s for s in ss), cache=False)
Hello, Foobar
['Hello, Fo, =;:<o', 'Hello, Bar']