merge: use any() instead of for loop when checking for dirty subrepos
I think it's both simpler and clearer to use any() than the current
for loop.
While at it, also drop the call to sorted(), since it doesn't matter
which order we iterate over subrepos.
#!/usr/bin/env python
#
# Based on python's Tools/scripts/md5sum.py
#
# This software may be used and distributed according to the terms
# of the PYTHON SOFTWARE FOUNDATION LICENSE VERSION 2, which is
# GPL-compatible.
import sys, os
try:
from hashlib import md5
except ImportError:
from md5 import md5
try:
import msvcrt
msvcrt.setmode(sys.stdout.fileno(), os.O_BINARY)
msvcrt.setmode(sys.stderr.fileno(), os.O_BINARY)
except ImportError:
pass
for filename in sys.argv[1:]:
try:
fp = open(filename, 'rb')
except IOError as msg:
sys.stderr.write('%s: Can\'t open: %s\n' % (filename, msg))
sys.exit(1)
m = md5()
try:
while True:
data = fp.read(8192)
if not data:
break
m.update(data)
except IOError as msg:
sys.stderr.write('%s: I/O error: %s\n' % (filename, msg))
sys.exit(1)
sys.stdout.write('%s %s\n' % (m.hexdigest(), filename))
sys.exit(0)