tests/test-lrucachedict.py
author Martin von Zweigbergk <martinvonz@google.com>
Tue, 23 Feb 2016 10:59:25 -0800
changeset 28226 377f0d8ff874
parent 27576 6cd3044985c2
child 28930 e3f01188d439
permissions -rw-r--r--
merge: use any() instead of for loop when checking for dirty subrepos I think it's both simpler and clearer to use any() than the current for loop. While at it, also drop the call to sorted(), since it doesn't matter which order we iterate over subrepos.

from mercurial import util

def printifpresent(d, xs, name='d'):
    for x in xs:
        present = x in d
        print "'%s' in %s: %s" % (x, name, present)
        if present:
            print "%s['%s']: %s" % (name, x, d[x])

def test_lrucachedict():
    d = util.lrucachedict(4)
    d['a'] = 'va'
    d['b'] = 'vb'
    d['c'] = 'vc'
    d['d'] = 'vd'

    # all of these should be present
    printifpresent(d, ['a', 'b', 'c', 'd'])

    # 'a' should be dropped because it was least recently used
    d['e'] = 've'
    printifpresent(d, ['a', 'b', 'c', 'd', 'e'])

    # touch entries in some order (get or set).
    d['e']
    d['c'] = 'vc2'
    d['d']
    d['b'] = 'vb2'

    # 'e' should be dropped now
    d['f'] = 'vf'
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

    d.clear()
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

    # Now test dicts that aren't full.
    d = util.lrucachedict(4)
    d['a'] = 1
    d['b'] = 2
    d['a']
    d['b']
    printifpresent(d, ['a', 'b'])

    # test copy method
    d = util.lrucachedict(4)
    d['a'] = 'va3'
    d['b'] = 'vb3'
    d['c'] = 'vc3'
    d['d'] = 'vd3'

    dc = d.copy()

    # all of these should be present
    print "\nAll of these should be present:"
    printifpresent(dc, ['a', 'b', 'c', 'd'], 'dc')

    # 'a' should be dropped because it was least recently used
    print "\nAll of these except 'a' should be present:"
    dc['e'] = 've3'
    printifpresent(dc, ['a', 'b', 'c', 'd', 'e'], 'dc')

    # contents and order of original dict should remain unchanged
    print "\nThese should be in reverse alphabetical order and read 'v?3':"
    dc['b'] = 'vb3_new'
    for k in list(iter(d)):
        print "d['%s']: %s" % (k, d[k])

if __name__ == '__main__':
    test_lrucachedict()