merge: use any() instead of for loop when checking for dirty subrepos
I think it's both simpler and clearer to use any() than the current
for loop.
While at it, also drop the call to sorted(), since it doesn't matter
which order we iterate over subrepos.
from mercurial import util
def printifpresent(d, xs, name='d'):
for x in xs:
present = x in d
print "'%s' in %s: %s" % (x, name, present)
if present:
print "%s['%s']: %s" % (name, x, d[x])
def test_lrucachedict():
d = util.lrucachedict(4)
d['a'] = 'va'
d['b'] = 'vb'
d['c'] = 'vc'
d['d'] = 'vd'
# all of these should be present
printifpresent(d, ['a', 'b', 'c', 'd'])
# 'a' should be dropped because it was least recently used
d['e'] = 've'
printifpresent(d, ['a', 'b', 'c', 'd', 'e'])
# touch entries in some order (get or set).
d['e']
d['c'] = 'vc2'
d['d']
d['b'] = 'vb2'
# 'e' should be dropped now
d['f'] = 'vf'
printifpresent(d, ['b', 'c', 'd', 'e', 'f'])
d.clear()
printifpresent(d, ['b', 'c', 'd', 'e', 'f'])
# Now test dicts that aren't full.
d = util.lrucachedict(4)
d['a'] = 1
d['b'] = 2
d['a']
d['b']
printifpresent(d, ['a', 'b'])
# test copy method
d = util.lrucachedict(4)
d['a'] = 'va3'
d['b'] = 'vb3'
d['c'] = 'vc3'
d['d'] = 'vd3'
dc = d.copy()
# all of these should be present
print "\nAll of these should be present:"
printifpresent(dc, ['a', 'b', 'c', 'd'], 'dc')
# 'a' should be dropped because it was least recently used
print "\nAll of these except 'a' should be present:"
dc['e'] = 've3'
printifpresent(dc, ['a', 'b', 'c', 'd', 'e'], 'dc')
# contents and order of original dict should remain unchanged
print "\nThese should be in reverse alphabetical order and read 'v?3':"
dc['b'] = 'vb3_new'
for k in list(iter(d)):
print "d['%s']: %s" % (k, d[k])
if __name__ == '__main__':
test_lrucachedict()