tests/seq.py
author Manuel Jacob <me@manueljacob.de>
Sun, 22 May 2022 03:50:34 +0200
changeset 49269 395f28064826
parent 48875 6000f5b25c9b
child 49285 56f98406831b
permissions -rwxr-xr-x
worker: avoid potential partial write of pickled data Previously, the code wrote the pickled data using os.write(). However, os.write() can write less bytes than passed to it. To trigger the problem, the pickled data had to be larger than 2147479552 bytes on my system. Instead, open a file object and pass it to pickle.dump(). This also has the advantage that it doesn’t buffer the whole pickled data in memory. Note that the opened file must be buffered because pickle doesn’t support unbuffered streams because unbuffered streams’ write() method might write less bytes than passed to it (like os.write()) but pickle.dump() relies on that all bytes are written (see https://github.com/python/cpython/issues/93050). The side effect of using a file object and a with statement is that wfd is explicitly closed now while it seems like before it was implicitly closed by process exit.

#!/usr/bin/env python3
#
# A portable replacement for 'seq'
#
# Usage:
#   seq STOP              [1, STOP] stepping by 1
#   seq START STOP        [START, STOP] stepping by 1
#   seq START STEP STOP   [START, STOP] stepping by STEP

import os
import sys

try:
    import msvcrt

    msvcrt.setmode(sys.stdin.fileno(), os.O_BINARY)
    msvcrt.setmode(sys.stdout.fileno(), os.O_BINARY)
    msvcrt.setmode(sys.stderr.fileno(), os.O_BINARY)
except ImportError:
    pass

if sys.version_info[0] >= 3:
    xrange = range

start = 1
if len(sys.argv) > 2:
    start = int(sys.argv[1])

step = 1
if len(sys.argv) > 3:
    step = int(sys.argv[2])

stop = int(sys.argv[-1]) + 1

for i in xrange(start, stop, step):
    print(i)