Mercurial > hg
view mercurial/parser.py @ 25350:48b1d8944406
revert: remove unused debug code in the test file
I left a test environment variable in a previous commit and it is doing nothing
useful. This patch removes it.
author | Laurent Charignon <lcharignon@fb.com> |
---|---|
date | Fri, 29 May 2015 10:34:12 -0700 |
parents | c87b05925054 |
children | af329a84310c |
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# parser.py - simple top-down operator precedence parser for mercurial # # Copyright 2010 Matt Mackall <mpm@selenic.com> # # This software may be used and distributed according to the terms of the # GNU General Public License version 2 or any later version. # see http://effbot.org/zone/simple-top-down-parsing.htm and # http://eli.thegreenplace.net/2010/01/02/top-down-operator-precedence-parsing/ # for background # takes a tokenizer and elements # tokenizer is an iterator that returns type, value pairs # elements is a mapping of types to binding strength, prefix and infix actions # an action is a tree node name, a tree label, and an optional match # __call__(program) parses program into a labeled tree import error from i18n import _ class parser(object): def __init__(self, tokenizer, elements, methods=None): self._tokenizer = tokenizer self._elements = elements self._methods = methods self.current = None def _advance(self): 'advance the tokenizer' t = self.current self.current = next(self._iter, None) return t def _match(self, m, pos): 'make sure the tokenizer matches an end condition' if self.current[0] != m: raise error.ParseError(_("unexpected token: %s") % self.current[0], self.current[2]) self._advance() def _parse(self, bind=0): token, value, pos = self._advance() # handle prefix rules on current token prefix = self._elements[token][1] if not prefix: raise error.ParseError(_("not a prefix: %s") % token, pos) if len(prefix) == 1: expr = (prefix[0], value) else: if len(prefix) > 2 and prefix[2] == self.current[0]: self._match(prefix[2], pos) expr = (prefix[0], None) else: expr = (prefix[0], self._parse(prefix[1])) if len(prefix) > 2: self._match(prefix[2], pos) # gather tokens until we meet a lower binding strength while bind < self._elements[self.current[0]][0]: token, value, pos = self._advance() e = self._elements[token] # check for suffix - next token isn't a valid prefix if len(e) == 4 and not self._elements[self.current[0]][1]: suffix = e[3] expr = (suffix[0], expr) else: # handle infix rules if len(e) < 3 or not e[2]: raise error.ParseError(_("not an infix: %s") % token, pos) infix = e[2] if len(infix) == 3 and infix[2] == self.current[0]: self._match(infix[2], pos) expr = (infix[0], expr, (None)) else: expr = (infix[0], expr, self._parse(infix[1])) if len(infix) == 3: self._match(infix[2], pos) return expr def parse(self, message, lookup=None): 'generate a parse tree from a message' if lookup: self._iter = self._tokenizer(message, lookup) else: self._iter = self._tokenizer(message) self._advance() res = self._parse() token, value, pos = self.current return res, pos def eval(self, tree): 'recursively evaluate a parse tree using node methods' if not isinstance(tree, tuple): return tree return self._methods[tree[0]](*[self.eval(t) for t in tree[1:]]) def __call__(self, message): 'parse a message into a parse tree and evaluate if methods given' t = self.parse(message) if self._methods: return self.eval(t) return t def _prettyformat(tree, leafnodes, level, lines): if not isinstance(tree, tuple) or tree[0] in leafnodes: lines.append((level, str(tree))) else: lines.append((level, '(%s' % tree[0])) for s in tree[1:]: _prettyformat(s, leafnodes, level + 1, lines) lines[-1:] = [(lines[-1][0], lines[-1][1] + ')')] def prettyformat(tree, leafnodes): lines = [] _prettyformat(tree, leafnodes, 0, lines) output = '\n'.join((' ' * l + s) for l, s in lines) return output def simplifyinfixops(tree, targetnodes): """Flatten chained infix operations to reduce usage of Python stack >>> def f(tree): ... print prettyformat(simplifyinfixops(tree, ('or',)), ('symbol',)) >>> f(('or', ... ('or', ... ('symbol', '1'), ... ('symbol', '2')), ... ('symbol', '3'))) (or ('symbol', '1') ('symbol', '2') ('symbol', '3')) >>> f(('func', ... ('symbol', 'p1'), ... ('or', ... ('or', ... ('func', ... ('symbol', 'sort'), ... ('list', ... ('or', ... ('or', ... ('symbol', '1'), ... ('symbol', '2')), ... ('symbol', '3')), ... ('negate', ... ('symbol', 'rev')))), ... ('and', ... ('symbol', '4'), ... ('group', ... ('or', ... ('or', ... ('symbol', '5'), ... ('symbol', '6')), ... ('symbol', '7'))))), ... ('symbol', '8')))) (func ('symbol', 'p1') (or (func ('symbol', 'sort') (list (or ('symbol', '1') ('symbol', '2') ('symbol', '3')) (negate ('symbol', 'rev')))) (and ('symbol', '4') (group (or ('symbol', '5') ('symbol', '6') ('symbol', '7')))) ('symbol', '8'))) """ if not isinstance(tree, tuple): return tree op = tree[0] if op not in targetnodes: return (op,) + tuple(simplifyinfixops(x, targetnodes) for x in tree[1:]) # walk down left nodes taking each right node. no recursion to left nodes # because infix operators are left-associative, i.e. left tree is deep. # e.g. '1 + 2 + 3' -> (+ (+ 1 2) 3) -> (+ 1 2 3) simplified = [] x = tree while x[0] == op: l, r = x[1:] simplified.append(simplifyinfixops(r, targetnodes)) x = l simplified.append(simplifyinfixops(x, targetnodes)) simplified.append(op) return tuple(reversed(simplified))