view tests/test-bdiff.py @ 17920:4a4173519b63

run-tests: remove resultslock since it serves no useful purpose Each child process has its own copy of the results dict, so all access to the results dict is serial.
author Siddharth Agarwal <sid0@fb.com>
date Fri, 09 Nov 2012 15:09:35 -0800
parents eeac5e179243
children 2e54aaa65afc
line wrap: on
line source

import struct
from mercurial import bdiff, mpatch

def test1(a, b):
    d = bdiff.bdiff(a, b)
    c = a
    if d:
        c = mpatch.patches(a, [d])
    if c != b:
        print "***", repr(a), repr(b)
        print "bad:"
        print repr(c)[:200]
        print repr(d)

def test(a, b):
    print "***", repr(a), repr(b)
    test1(a, b)
    test1(b, a)

test("a\nc\n\n\n\n", "a\nb\n\n\n")
test("a\nb\nc\n", "a\nc\n")
test("", "")
test("a\nb\nc", "a\nb\nc")
test("a\nb\nc\nd\n", "a\nd\n")
test("a\nb\nc\nd\n", "a\nc\ne\n")
test("a\nb\nc\n", "a\nc\n")
test("a\n", "c\na\nb\n")
test("a\n", "")
test("a\n", "b\nc\n")
test("a\n", "c\na\n")
test("", "adjfkjdjksdhfksj")
test("", "ab")
test("", "abc")
test("a", "a")
test("ab", "ab")
test("abc", "abc")
test("a\n", "a\n")
test("a\nb", "a\nb")

#issue1295
def showdiff(a, b):
    bin = bdiff.bdiff(a, b)
    pos = 0
    while pos < len(bin):
        p1, p2, l = struct.unpack(">lll", bin[pos:pos + 12])
        pos += 12
        print p1, p2, repr(bin[pos:pos + l])
        pos += l
showdiff("x\n\nx\n\nx\n\nx\n\nz\n", "x\n\nx\n\ny\n\nx\n\nx\n\nz\n")
showdiff("x\n\nx\n\nx\n\nx\n\nz\n", "x\n\nx\n\ny\n\nx\n\ny\n\nx\n\nz\n")

print "done"

def testfixws(a, b, allws):
    c = bdiff.fixws(a, allws)
    if c != b:
        print "*** fixws", repr(a), repr(b), allws
        print "got:"
        print repr(c)

testfixws(" \ta\r b\t\n", "ab\n", 1)
testfixws(" \ta\r b\t\n", " a b\n", 0)
testfixws("", "", 1)
testfixws("", "", 0)

print "done"