view mercurial/strutil.py @ 20555:4add43865a9b

ancestors: remove unnecessary handling of 'left' If one of the initial nodes also is an ancestor then that most be the only ancestor. There is no need for additional bookkeeping.
author Mads Kiilerich <madski@unity3d.com>
date Mon, 24 Feb 2014 22:42:13 +0100
parents 25e572394f5c
children b723f05ec49b
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# strutil.py - string utilities for Mercurial
#
# Copyright 2006 Vadim Gelfer <vadim.gelfer@gmail.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.

def findall(haystack, needle, start=0, end=None):
    if end is None:
        end = len(haystack)
    if end < 0:
        end += len(haystack)
    if start < 0:
        start += len(haystack)
    while start < end:
        c = haystack.find(needle, start, end)
        if c == -1:
            break
        yield c
        start = c + 1

def rfindall(haystack, needle, start=0, end=None):
    if end is None:
        end = len(haystack)
    if end < 0:
        end += len(haystack)
    if start < 0:
        start += len(haystack)
    while end >= 0:
        c = haystack.rfind(needle, start, end)
        if c == -1:
            break
        yield c
        end = c - 1