view mercurial/ancestor.py @ 17758:5863f0e4cd3a

histedit: replace various nodes lists with replacement graph (and issue3582) This changeset rewrites the change tracking logic of histedit to record every operation it does. Tracked operations record the full list of "old" node that will eventually be removed to the list of new nodes that replace it. Operations on temporary nodes are tracked too. Dropped changesets are also recorded as an "old" node replacement by nothing. This logic is similar to the obsolescence marker one and will be used for this purpose in later commit. This new logic implies a big amount of change in the histedit code base. histedit action functions now always return a tuple of (new-ctx, [list of rewriting operations]) The old `created`, `replaced` and `tmpnodes` are no longer returned and stored during histedit operation. When such information is necessary it is computed from the replacement graph. This computation is done in the `processreplacement` function. The `replacemap` is also dropped. It is computed at the end of the command from the graph. The `bootstrapcontinue` methods are altered to compute this different kind of information. This new mechanism requires much less information to be written on disk. Note: This changes allows a more accurate bookmark movement. bookmark on dropped changeset are now move of their parent (or replacement of their parent) instead of their children. This fix issue3582
author Pierre-Yves David <pierre-yves.david@ens-lyon.org>
date Thu, 11 Oct 2012 08:36:50 +0200
parents 1ffeeb91c55d
children 0b03454abae7
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# ancestor.py - generic DAG ancestor algorithm for mercurial
#
# Copyright 2006 Matt Mackall <mpm@selenic.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.

import heapq

def ancestor(a, b, pfunc):
    """
    Returns the common ancestor of a and b that is furthest from a
    root (as measured by longest path) or None if no ancestor is
    found. If there are multiple common ancestors at the same
    distance, the first one found is returned.

    pfunc must return a list of parent vertices for a given vertex
    """

    if a == b:
        return a

    a, b = sorted([a, b])

    # find depth from root of all ancestors
    # depth is stored as a negative for heapq
    parentcache = {}
    visit = [a, b]
    depth = {}
    while visit:
        vertex = visit[-1]
        pl = pfunc(vertex)
        parentcache[vertex] = pl
        if not pl:
            depth[vertex] = 0
            visit.pop()
        else:
            for p in pl:
                if p == a or p == b: # did we find a or b as a parent?
                    return p # we're done
                if p not in depth:
                    visit.append(p)
            if visit[-1] == vertex:
                # -(maximum distance of parents + 1)
                depth[vertex] = min([depth[p] for p in pl]) - 1
                visit.pop()

    # traverse ancestors in order of decreasing distance from root
    def ancestors(vertex):
        h = [(depth[vertex], vertex)]
        seen = set()
        while h:
            d, n = heapq.heappop(h)
            if n not in seen:
                seen.add(n)
                yield (d, n)
                for p in parentcache[n]:
                    heapq.heappush(h, (depth[p], p))

    def generations(vertex):
        sg, s = None, set()
        for g, v in ancestors(vertex):
            if g != sg:
                if sg:
                    yield sg, s
                sg, s = g, set((v,))
            else:
                s.add(v)
        yield sg, s

    x = generations(a)
    y = generations(b)
    gx = x.next()
    gy = y.next()

    # increment each ancestor list until it is closer to root than
    # the other, or they match
    try:
        while True:
            if gx[0] == gy[0]:
                for v in gx[1]:
                    if v in gy[1]:
                        return v
                gy = y.next()
                gx = x.next()
            elif gx[0] > gy[0]:
                gy = y.next()
            else:
                gx = x.next()
    except StopIteration:
        return None