rust-cpython: move $leaked struct out of macro
It wasn't easy to hack the $leaked struct since errors in macro would
generate lots of compile errors. Let's make it a plain struct so we can
easily extend it.
PyLeakedRef keeps a more generic PyObject instead of the $name struct
since it no longer has to call any specific methods implemented by
the $name class. $leaked parameter in py_shared_iterator!() is kept
for future change.
from __future__ import absolute_import, print_function
import os
import sys
import unittest
def main(modulename):
'''run the tests found in module, printing nothing when all tests pass'''
module = sys.modules[modulename]
suite = unittest.defaultTestLoader.loadTestsFromModule(module)
results = unittest.TestResult()
suite.run(results)
if results.errors or results.failures:
for tc, exc in results.errors:
print('ERROR:', tc)
print()
sys.stdout.write(exc)
for tc, exc in results.failures:
print('FAIL:', tc)
print()
sys.stdout.write(exc)
sys.exit(1)
if os.environ.get('SILENT_BE_NOISY'):
main = unittest.main