rust-cpython: move $leaked struct out of macro
It wasn't easy to hack the $leaked struct since errors in macro would
generate lots of compile errors. Let's make it a plain struct so we can
easily extend it.
PyLeakedRef keeps a more generic PyObject instead of the $name struct
since it no longer has to call any specific methods implemented by
the $name class. $leaked parameter in py_shared_iterator!() is kept
for future change.
running: init test1
result: 0
running: add foo
result: 0
running: commit -m commit1 -d 2000-01-01 foo
result: 0
running: commit -m commit2 -d 2000-01-02 foo
result: 0
running: log -r 0
changeset: 0:0e4634943879
user: test
date: Sat Jan 01 00:00:00 2000 +0000
summary: commit1
result: 0
running: log -r tip
changeset: 1:45589e459b2e
tag: tip
user: test
date: Sun Jan 02 00:00:00 2000 +0000
summary: commit2
result: 0