backout: don't limit heritage check to a single ancestor
This do probably not make any real difference but is slightly more correct and
we would like to get rid of changelog.ancestor.
import struct
from mercurial import bdiff, mpatch
def test1(a, b):
d = bdiff.bdiff(a, b)
c = a
if d:
c = mpatch.patches(a, [d])
if c != b:
print "***", repr(a), repr(b)
print "bad:"
print repr(c)[:200]
print repr(d)
def test(a, b):
print "***", repr(a), repr(b)
test1(a, b)
test1(b, a)
test("a\nc\n\n\n\n", "a\nb\n\n\n")
test("a\nb\nc\n", "a\nc\n")
test("", "")
test("a\nb\nc", "a\nb\nc")
test("a\nb\nc\nd\n", "a\nd\n")
test("a\nb\nc\nd\n", "a\nc\ne\n")
test("a\nb\nc\n", "a\nc\n")
test("a\n", "c\na\nb\n")
test("a\n", "")
test("a\n", "b\nc\n")
test("a\n", "c\na\n")
test("", "adjfkjdjksdhfksj")
test("", "ab")
test("", "abc")
test("a", "a")
test("ab", "ab")
test("abc", "abc")
test("a\n", "a\n")
test("a\nb", "a\nb")
#issue1295
def showdiff(a, b):
bin = bdiff.bdiff(a, b)
pos = 0
while pos < len(bin):
p1, p2, l = struct.unpack(">lll", bin[pos:pos + 12])
pos += 12
print p1, p2, repr(bin[pos:pos + l])
pos += l
showdiff("x\n\nx\n\nx\n\nx\n\nz\n", "x\n\nx\n\ny\n\nx\n\nx\n\nz\n")
showdiff("x\n\nx\n\nx\n\nx\n\nz\n", "x\n\nx\n\ny\n\nx\n\ny\n\nx\n\nz\n")
print "done"
def testfixws(a, b, allws):
c = bdiff.fixws(a, allws)
if c != b:
print "*** fixws", repr(a), repr(b), allws
print "got:"
print repr(c)
testfixws(" \ta\r b\t\n", "ab\n", 1)
testfixws(" \ta\r b\t\n", " a b\n", 0)
testfixws("", "", 1)
testfixws("", "", 0)
print "done"