view mercurial/pure/base85.py @ 8564:6b9ec23b09fc

named branches: improve pre-push logic (issue736)

Each named branch is considered separately, and the push is allowed if
no new branch heads are created for any named branch to be pushed.

Due to some tests's use of --debug, their output will change after this
addition. This has been fixed as well.

Co-contributor: Henrik Stuart <[e-mail]>

# base85.py: pure python base85 codec
#
# Copyright (C) 2009 Brendan Cully <[e-mail]>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2, incorporated herein by reference.

import struct

_b85chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" \
            "abcdefghijklmnopqrstuvwxyz!#$%&()*+-;<=>?@^_`{|}~"
_b85chars2 = [(a + b) for a in _b85chars for b in _b85chars]
_b85dec = {}

def _mkb85dec():
    for i in range(len(_b85chars)):
        _b85dec[_b85chars[i]] = i

def b85encode(text, pad=False):
    """encode text in base85 format"""
    l = len(text)
    r = l % 4
    if r:
        text += '\0' * (4 - r)
    longs = len(text) >> 2
    words = struct.unpack('>%dL' % (longs), text)

    out = ''.join(_b85chars[(word / 52200625) % 85] +
                  _b85chars2[(word / 7225) % 7225] +
                  _b85chars2[word % 7225]
                  for word in words)

    if pad:
        return out

    # Trim padding
    olen = l % 4
    if olen:
        olen += 1
    olen += l / 4 * 5
    return out[:olen]

def b85decode(text):
    """decode base85-encoded text"""
    if not _b85dec:
        _mkb85dec()

    l = len(text)
    out = []
    for i in range(0, len(text), 5):
        chunk = text[i:i+5]
        acc = 0
        for j in range(len(chunk)):
            try:
                acc = acc * 85 + _b85dec[chunk[j]]
            except KeyError:
                raise TypeError('Bad base85 character at byte %d' % (i + j))
        if acc > 4294967295:
            raise OverflowError('Base85 overflow in hunk starting at byte %d' % i)
        out.append(acc)

    # Pad final chunk if necessary
    cl = l % 5
    if cl:
        acc *= 85 ** (5 - cl)
        if cl > 1:
            acc += 0xffffff >> (cl - 2) * 8
        out[-1] = acc

    out = struct.pack('>%dL' % (len(out)), *out)
    if cl:
        out = out[:-(5 - cl)]

    return out