Mercurial > hg
view tests/test-lrucachedict.py @ 29954:769aee32fae0
strip: don't use "full" and "partial" to describe bundles
The partial bundle is not a subset of the full bundle, and the full
bundle is not full in any way that i see. The most obvious
interpretation of "full" I can think of is that it has all commits
back to the null revision, but that is not what the "full" bundle
is. The "full" bundle is simply a backup of what the user asked us to
strip (unless --no-backup). The "partial" bundle contains the
revisions we temporarily stripped because they had higher revision
numbers that some commit that the user asked us to strip.
The "full" bundle is already called "backup" in the code, so let's use
that in user-facing messages too. Let's call the "partial" bundle
"temporary" in the code.
author | Martin von Zweigbergk <martinvonz@google.com> |
---|---|
date | Mon, 19 Sep 2016 09:14:35 -0700 |
parents | 79add5a4e857 |
children | 067f7d2c7d60 |
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from __future__ import absolute_import, print_function from mercurial import ( util, ) def printifpresent(d, xs, name='d'): for x in xs: present = x in d print("'%s' in %s: %s" % (x, name, present)) if present: print("%s['%s']: %s" % (name, x, d[x])) def test_lrucachedict(): d = util.lrucachedict(4) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' d['d'] = 'vd' # all of these should be present printifpresent(d, ['a', 'b', 'c', 'd']) # 'a' should be dropped because it was least recently used d['e'] = 've' printifpresent(d, ['a', 'b', 'c', 'd', 'e']) assert d.get('a') is None assert d.get('e') == 've' # touch entries in some order (get or set). d['e'] d['c'] = 'vc2' d['d'] d['b'] = 'vb2' # 'e' should be dropped now d['f'] = 'vf' printifpresent(d, ['b', 'c', 'd', 'e', 'f']) d.clear() printifpresent(d, ['b', 'c', 'd', 'e', 'f']) # Now test dicts that aren't full. d = util.lrucachedict(4) d['a'] = 1 d['b'] = 2 d['a'] d['b'] printifpresent(d, ['a', 'b']) # test copy method d = util.lrucachedict(4) d['a'] = 'va3' d['b'] = 'vb3' d['c'] = 'vc3' d['d'] = 'vd3' dc = d.copy() # all of these should be present print("\nAll of these should be present:") printifpresent(dc, ['a', 'b', 'c', 'd'], 'dc') # 'a' should be dropped because it was least recently used print("\nAll of these except 'a' should be present:") dc['e'] = 've3' printifpresent(dc, ['a', 'b', 'c', 'd', 'e'], 'dc') # contents and order of original dict should remain unchanged print("\nThese should be in reverse alphabetical order and read 'v?3':") dc['b'] = 'vb3_new' for k in list(iter(d)): print("d['%s']: %s" % (k, d[k])) if __name__ == '__main__': test_lrucachedict()